A nurse is caring for a client who has pneumonia caused by Haemophilus influenzae type B. Which of the following types of isolation precautions should the nurse implement?
Protective environment
Droplet
Airborne
Contact
The Correct Answer is B
Rationale:
A. Protective environment: Protective environment precautions are used for clients with compromised immune systems (e.g., transplant patients), not for those with bacterial pneumonia caused by Haemophilus influenzae type B.
B. Droplet: Haemophilus influenzae type B is spread through respiratory droplets, so droplet precautions are appropriate. The nurse should wear a mask when within 3 feet of the client to prevent transmission.
C. Airborne: Airborne precautions are used for diseases transmitted through small particles in the air, such as tuberculosis or measles, but are not necessary for Haemophilus influenzae type B, which is droplet-transmitted.
D. Contact: Contact precautions are used for infections spread by direct or indirect contact with the patient or their environment, such as Clostridium difficile or MRSA, but not for Haemophilus influenzae type B pneumonia.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["A","B","C","D","E","H","I"]
Explanation
Findings that indicate the client has a potential problem:
- Chest pain radiating to left arm: Chest pain that radiates to the left arm is a classic symptom of a myocardial infarction (MI). The description of pain (tightness) and its radiation to the left arm are a red flag for an acute cardiac event, which requires immediate intervention.
- Pain level of 7 on a scale of 0 to 10: A pain level of 7 indicates significant discomfort, and when combined with other symptoms like chest tightness and radiation to the left arm, it further supports the possibility of a myocardial infarction.
- Started to feel nauseous after breakfast: Nausea can be an associated symptom of acute myocardial infarction (MI), especially in women, the elderly, and those with diabetes. Its presence, along with chest pain, is concerning.
- Diaphoresis: Diaphoresis (excessive sweating) is often associated with myocardial infarction and is a key sign of acute coronary syndrome. This finding, along with chest pain and shortness of breath, suggests an emergent situation.
- Tachycardia with irregular heart rate: The client’s heart rate is 110/min and irregular, which can be indicative of arrhythmias commonly seen in acute myocardial infarction. The irregular and tachycardic rhythm should be immediately evaluated to prevent further complications.
- +1 pedal pulses: While present, +1 pedal pulses are diminished. This could indicate compromised peripheral circulation, possibly related to overall cardiovascular compromise or underlying peripheral artery disease, which is often co-morbid with the client's existing conditions (hyperlipidemia, hypertension, diabetes).
- Skin is cool to touch: Cool skin, especially when accompanied by other signs of poor perfusion like diminished pulses, can indicate reduced peripheral blood flow, which may be a systemic response to decreased cardiac output from a significant cardiac event.
Rationale for Incorrect Findings:
- Lungs clear to auscultation: Clear lung sounds suggest no signs of pulmonary edema or other lung issues at the moment, ruling out respiratory causes of the symptoms.
- Bowel sounds present in all 4 quadrants: The presence of bowel sounds in all quadrants is normal and suggests that the gastrointestinal system is functioning well.
- Capillary refill less than 2 seconds is normal and indicate adequate perfusion, this finding on its own does not require follow up.
Correct Answer is {"dropdown-group-1":"A","dropdown-group-2":"B"}
Explanation
Rationale:
- 1320 mL in the first hour The provider has prescribed 15 mL/kg/hr of 0.9% sodium chloride for the first hour. The client weighs 88 kg, so the calculation is 88 kg × 15 mL/kg = 1320 mL to be administered in the first hour.
- 880 mL in the subsequent hour: After the first hour, the rate is reduced to 10 mL/kg/hr. Using the same weight of 88 kg, the calculation for the next hour is 88 kg × 10 mL/kg = 880 mL to be administered in the second hour.
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