A nurse is preparing to administer cefazolin 250 mg via intermittent IV bolus every 8 hr. Available is cefazolin 500 mg vial.
The package insert instructs to add 2 mL of sterile water to yield a concentration of 225 mg/mL and then add to 50 mL of 0.9% sodium chloride.
How many mL of cefazolin should the nurse add to the 50 mL of 0.9% sodium chloride? (Round the answer to the nearest tenth.
Use a leading zero if it applies.
Do not use a trailing zero.). mL. .
The Correct Answer is ["1.1"]
Step 1: Calculate the volume of cefazolin needed for a 250 mg dose.
Volume of cefazolin = 250 mg ÷ 225 mg/mL = 1.11 mLStep 2: Round the answer to the nearest tenth.
1.11 mL rounded to the nearest tenth is 1.1 mL.Therefore, the nurse should add 1.1 mL of cefazolin to the 50 mL of 0.9% sodium chloride.
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Related Questions
Correct Answer is ["2"]
Explanation
Step 1 is to determine the amount of medication needed. The order is for 1 g and the available medication is 1 g/10 mL. So, we calculate 1 g ÷ 1 g/10 mL = 10 mL. Since 1 tsp is approximately 5 mL, we then calculate 10 mL ÷ 5 mL/tsp = 2 tsp. So the correct answer is 2 tsp.
Correct Answer is ["2.1"]
Explanation
First, we need to calculate the total daily dose of tobramycin for the client. The total daily dose is calculated as follows:
Total daily dose = Dose per kg per day x Weight Total daily dose = 3 mg/kg/day x 85 kg Total daily dose = 255 mg/day
Since the total daily dose is divided into three doses, each dose will be:
Each dose = Total daily dose / Number of doses Each dose = 255 mg / 3 Each dose = 85 mg
Now, we need to convert this dose into mL. We know that we have tobramycin 40 mg/mL, so:
Volume to administer = Each dose / Concentration Volume to administer = 85 mg / 40 mg/mL Volume to administer = 2.125 mL
Rounding this to the nearest tenth, we get 2.1 mL.
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