A patient is receiving an IV of esmolol 2.5 grams in 250 mL of D5W (dextrose 5% in water) infusing at 200 micrograms/kilogram/minute. The patient weighs 110 lb. What rate (in mL/hr) should the nurse program into the IV pump to deliver this dose?
45 mL/hr
60 mL/hr
75 mL/hr
90 mL/hr
The Correct Answer is B
Step 1 is Convert pounds to kilograms 110 lb ÷ 2.2 = 50 kg
Step 2 is Calculate dose in micrograms per minute 50 kg × 200 micrograms = 10,000 micrograms/min
Step 3 is Convert micrograms to milligrams 10,000 micrograms ÷ 1000 = 10 mg/min
Step 4 is Convert mg/min to mg/hr 10 mg × 60 = 600 mg/hr
Step 5 is Determine concentration of esmolol in mg/mL 2.5 grams × 1000 = 2500 mg 2500 mg ÷ 250 mL = 10 mg/mL
Step 6 is Calculate infusion rate in mL/hr 600 mg/hr ÷ 10 mg/mL = 60 mL/hr
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Related Questions
Correct Answer is C
Explanation
The nurse should add 250 mL of water to the formula to dilute it to half strength.
This answer is correct because it is based on a simple ratio and proportion calculation. The nurse can set up a proportion as follows:
250 mL / 1 = x mL / 0.5
Cross-multiplying and solving for x gives:
x = 500 mL
Therefore, the nurse should add 250 mL of water to the formula to make a total volume of 500 mL, which is half the concentration of the original formula.
Correct Answer is B
Explanation
The infusion will be completed at 3:15 p.m.
This answer is correct because it is based on a simple division and addition calculation. The nurse should follow these steps to determine when the infusion will be completed:
1) Convert the volume of the fluid from liters to milliliters by multiplying by 1000, since there are 1000 mL in 1 L. The volume of the fluid is 750 mL.
2) Divide the volume of the fluid by the infusion rate to get the duration of the infusion in hours, as follows:
750 mL / 120 mL/hr = 6.25 hr
Therefore, the infusion will take 6.25 hours to complete.
3) Add the duration of the infusion to the start time of the infusion to get the end time, as follows:
9:00 a.m. + 6:25 = 3:15 p.m.
Therefore, the infusion will be completed at 3:15 p.m.
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