A patient is receiving an IV of esmolol 2.5 grams in 250 mL of D5W (dextrose 5% in water) infusing at 200 micrograms/kilogram/minute. The patient weighs 110 lb. What rate (in mL/hr) should the nurse program into the IV pump to deliver this dose?
45 mL/hr
60 mL/hr
75 mL/hr
90 mL/hr
The Correct Answer is B
Step 1 is Convert pounds to kilograms 110 lb ÷ 2.2 = 50 kg
Step 2 is Calculate dose in micrograms per minute 50 kg × 200 micrograms = 10,000 micrograms/min
Step 3 is Convert micrograms to milligrams 10,000 micrograms ÷ 1000 = 10 mg/min
Step 4 is Convert mg/min to mg/hr 10 mg × 60 = 600 mg/hr
Step 5 is Determine concentration of esmolol in mg/mL 2.5 grams × 1000 = 2500 mg 2500 mg ÷ 250 mL = 10 mg/mL
Step 6 is Calculate infusion rate in mL/hr 600 mg/hr ÷ 10 mg/mL = 60 mL/hr
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Related Questions
Correct Answer is B
Explanation
The nurse should administer 1050 mg of medication to achieve the total prescribed dose.
This answer is correct because it is based on a simple multiplication calculation. The nurse can multiply the prescribed dose per kilogram by the weight of the client in kilograms to get the total dose in milligrams, as follows:
25 mg/kg x 42 kg = 1050 mg
Therefore, the nurse should administer 1050 mg of medication to the client.
Correct Answer is A
Explanation
To find how much medication to administer, you need to calculate the following:
- The volume of diphenhydramine in milliliters
- The infusion time in minutes
First, divide the dose of diphenhydramine by the concentration to get the volume in milliliters:
25 mg / 50 mg/mL = 0.5 mL diphenhydramine should be diluted in 10 to 20 mL of normal saline and infused over at least 2 minutes.
Therefore, the nurse should administer **0.5 mL** of diphenhydramine diluted in 10 to 20 mL of normal saline over **at least 2 minutes**.
The nurse should administer this medication **as soon as possible** after receiving the order and the medication from the pharmacy, as STAT means immediately or urgently. The nurse should also monitor the client for signs of improvement or adverse reactions.
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