A man is 6' 4" tall, and weighs 226 pounds. The ideal weight chart indicates that his maximum desirable weight is 204 pounds. What percentage overweight is this man?
296.
20%.
16.5%
10%.
Correct Answer : D
To find the percentage overweight, first calculate the difference between his actual weight and his maximum desirable weight.
226 pounds – 204 pounds
= 22 pounds.
To find percentage overweight, divide this difference with the maximum desirable weight and then multiply by 100%.
% overweight = × 100%
= 10.78%
≈ 10%
From the given options, 10% is the closest option.
Therefore, the correct answer is
D. 10%
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Related Questions
Correct Answer is A
Explanation
Set up a proportion where the ratios must be equal.
=
This can be solved by cross-multiplying:
200×𝑋=2×20
200𝑋=40
Now, solve for X by dividing both sides by 200:
𝑋= = 0.2
Thus, the value of X is 0.2.
Correct Answer is B
Explanation
To determine which option represents the largest amount, consider the values in a comparable format:
A. 73.9% (equivalent to 0.739)
B. 16.25 (a whole number, clearly more than any of the percentages if you consider their decimal forms)
C. 95% (equivalent to 0.95, which is the largest among the percentages)
D. 1.25% (equivalent to 0.0125)
B 16.25 is clearly the largest number here, as it surpasses all the percentages when converted into decimal or whole number forms.
Correct Answer is D
Explanation
To multiply fractions;
1. Multiply the numerators together:
39×6=234
2. Multiply the denominators together:
54×13=702
Thus, the product of the fractions is.
Next, simplify:
- Calculate the greatest common divisor (GCD) of 234 and 702. Both numbers are divisible by 234:
234÷234=1
702÷234=3
The simplified product of the fractions is.
Thus, the correct answer from the provided choices is: D 1/3
Correct Answer is A
Explanation
1-liter equals 1000 milliliters.
Given 3 liters, the calculation will be:
3liters×1000milliliters/liter
=3000milliliters
Thus, 3 liters of fluid contains 3000 milliliters.
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