A nurse is caring for an intubated and sedated geriatric client. What intervention is most appropriate for reducing the risk of a friction and shear injury?
Postpone daily bed bath
Elevate the client’s head of the bed to 45 degrees
Caregiver independently slides the client up in bed
Use a mechanical lift to reposition the client every 2 hours
The Correct Answer is D
Choice A reason: Postponing daily bed bath is not appropriate for reducing the risk of a friction and shear injury. Bed bath is a hygiene measure that helps to keep the skin clean and dry and prevent infection. Friction and shear are caused by the rubbing and pulling of the skin against the bed surface, not by the bed bath itself.
Choice B reason: Elevating the client’s head of the bed to 45 degrees is not appropriate for reducing the risk of a friction and shear injury. In fact, this may increase the risk as the client may slide down the bed due to gravity and cause more friction and shear on the skin. The head of the bed should be kept at the lowest possible angle, preferably less than 30 degrees, unless contraindicated by the client’s condition.
Choice C reason: Caregiver independently slides the client up in bed is not appropriate for reducing the risk of a friction and shear injury. This may cause more damage to the skin as the caregiver may exert excessive force and drag the client’s skin along the bed surface. The caregiver should use a draw sheet or a slide board to lift and reposition the client with the help of another person.
Choice D reason: Use a mechanical lift to reposition the client every 2 hours is the most appropriate intervention for reducing the risk of a friction and shear injury. A mechanical lift is a device that helps to transfer and reposition the client safely and comfortably. It reduces the friction and shear on the skin by lifting the client off the bed surface and avoiding any sliding or dragging. It also prevents the caregiver from injuring themselves by lifting the client manually. The client should be repositioned every 2 hours to relieve the pressure on the skin and prevent pressure ulcers.
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Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["A","C","D","E"]
Explanation
Choice A reason: Washing your hands thoroughly is an important measure to reduce the risk of infection. Hand washing is one of the most effective ways to prevent the transmission of germs that can cause diseases. Hand washing can remove dirt, bacteria, viruses, and other contaminants from the skin and prevent them from entering the body or spreading to others. The nurse should teach the client with AIDS to wash their hands frequently and properly, especially before and after eating, using the bathroom, touching their face, or handling any objects that may be contaminated.
Choice B reason: Avoiding cleaning your toothbrush with bleach is not a measure to reduce the risk of infection. Cleaning your toothbrush with bleach is not a recommended practice, as bleach is a harsh chemical that can damage the toothbrush and irritate the mouth. However, cleaning your toothbrush with bleach does not increase the risk of infection, as bleach can kill most germs that may be present on the toothbrush. The nurse should teach the client with AIDS to rinse their toothbrush with water after each use and replace it every 3 to 4 months or sooner if the bristles are worn or frayed.
Choice C reason: Avoiding raw fruits and vegetables is a measure to reduce the risk of infection. Raw fruits and vegetables may be contaminated with bacteria, parasites, or pesticides that can cause foodborne illnesses. The client with AIDS has a weakened immune system that cannot fight off these infections effectively and may develop serious complications, such as diarrhea, dehydration, or malnutrition. The nurse should teach the client with AIDS to wash, peel, or cook their fruits and vegetables before eating them and to avoid any that are bruised, moldy, or spoiled.
Choice D reason: Avoiding crowds is a measure to reduce the risk of infection. Crowds are places where many people gather and interact, such as public transportation, shopping malls, schools, or workplaces. Crowds increase the exposure to germs that can cause respiratory, gastrointestinal, or skin infections. The client with AIDS has a lowered resistance to these infections and may contract them more easily and severely. The nurse should teach the client with AIDS to avoid crowds as much as possible and to wear a mask, practice social distancing, and use hand sanitizer if they have to be in a crowded place.
Choice E reason: Not sharing toothpaste with family members is a measure to reduce the risk of infection. Sharing toothpaste with family members can transfer saliva, blood, or other body fluids that may contain germs that can cause oral, dental, or systemic infections. The client with AIDS is more susceptible to these infections and may also transmit the HIV virus to their family members through their body fluids. The nurse should teach the client with AIDS to use their own toothpaste and toothbrush and to store them separately from their family members' ones.
Correct Answer is A
Explanation
Choice A reason: Stage 4 is the remodeling stage of bone healing, which occurs from 6 to 12 weeks after the fracture. In this stage, the callus, which is a mass of fibrous tissue and cartilage that forms around the fracture site, is gradually resorbed and replaced by mature bone. The bone becomes stronger and more compact and regains its original shape and function.
Choice B reason: Stage 3 is the callus formation stage of bone healing, which occurs from 2 to 6 weeks after the fracture. In this stage, the granulation tissue, which is a soft tissue that fills the fracture gap, is replaced by a callus that bridges the fracture ends. The callus is composed of fibroblasts, chondroblasts, and osteoblasts that produce collagen, cartilage, and bone matrix. The callus stabilizes the fracture and prepares it for remodeling.
Choice C reason: Stage 5 is not a valid stage of bone healing. There are only four stages of bone healing: stage 1 is the inflammatory stage, stage 2 is the reparative stage, stage 3 is the callus formation stage, and stage 4 is the remodeling stage.
Choice D reason: Stage 1 is the inflammatory stage of bone healing, which occurs from the time of the fracture to 3 to 5 days after the fracture. In this stage, the blood vessels around the fracture site are ruptured and form a hematoma, which is a blood clot that surrounds the fracture ends. The hematoma triggers an inflammatory response that involves the release of cytokines, growth factors, and inflammatory cells that initiate the healing process. The hematoma also provides a scaffold for the granulation tissue to grow.
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