A patient is receiving an IV of 500 mL of D5W (dextrose 5% in water).
How many grams (g) of dextrose are contained in this IV solution?
10g
25g
50g
100g
The Correct Answer is B
Dextrose 5% in water (D5W) is an IV fluid that contains **5 grams of dextrose** per 100 mL of water². To calculate how many grams of dextrose are in 500 mL of D5W, you can use a simple proportion:
5 g / 100 mL = x g / 500 mL
Cross-multiply and solve for x:
x = (5 g * 500 mL) / 100 mL
x = 25 g
Therefore, there are **25 grams of dextrose** in 500 mL of D5W.

Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is B
Explanation
QD is an abbreviation for "quaque die" which means "every day" in Latin. However, QD is on the official "Do Not Use" list of the Joint Commission because it can be mistaken for QOD, which means "every other day" in Latin¹². This can lead to medication errors and patient harm. Therefore, the Joint Commission recommends writing "daily" instead of QD.
The other options are not on the official "Do Not Use" list of the Joint Commission. OS, PO, and OD are abbreviations for "oculus sinister" (left eye), "per os" (by mouth), and "oculus dexter" (right eye) respectively. They are commonly used in ophthalmology and pharmacy³. However, they should be used with caution and only when appropriate, as they can also be confused with other abbreviations or symbols.
Correct Answer is A
Explanation
To calculate the gt/min flow rate, we need to determine the total number of drops and divide it by the total time in minutes.
First, let's convert the volume from liters to milliliters:
1 L = 1000 mL
Next, we need to determine the total number of drops. This can be calculated using the drop factor and the volume of the solution:
Total drops = Volume (mL) * Drop factor
= 1000 mL * 15 gt/mL
= 15000 gt
Now, we need to calculate the flow rate in gt/min. We divide the total drops by the total time in minutes: Flow rate = Total drops / Total time (min)
= 15000 gt / 360 min
≈ 41.67 gt/min (rounded to the nearest whole number)
Therefore, the correct answer is:
a. 41.6 gt/min
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