A nurse is planning to teach a client about a high-potassium diet. Which of the following foods should the nurse instruct the client to eat? (Select all that apply.).
Sweet Potatoes.
Bananas.
Grapes.
Watermelon.
Correct Answer : A,B,D
The correct answer is choices A, B, and D. Here are the rationales for each choice:
Choice A rationale:
Sweet potatoes are an excellent source of potassium. One medium sweet potato contains about 542 mg of potassium, making it a great option for a high-potassium diet.
Choice B rationale:
Bananas are well-known for their high potassium content. A medium banana provides approximately 451 mg of potassium, which is beneficial for maintaining proper muscle and nerve function.
Choice C rationale:
Grapes are not particularly high in potassium compared to other fruits. They contain some potassium, but not enough to be considered a significant source for a high-potassium diet.
Choice D rationale:
Watermelon is a good source of potassium. Two wedges of watermelon contain about 640 mg of potassium, making it a suitable choice for increasing potassium intake.
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Related Questions
Correct Answer is B
Explanation
The correct answer is choice B) Administering sodium polystyrene sulfonate.
Choice A rationale:
Administering a potassium-sparing diuretic is not appropriate for a client with hyperkalemia (high potassium levels). Potassium-sparing diuretics would further increase potassium levels, worsening the condition.
Choice B rationale:
Sodium polystyrene sulfonate is used to treat hyperkalemia. It works by exchanging sodium ions for potassium ions in the intestines, which helps to lower serum potassium levels by excreting it through the stool.
Choice C rationale:
Initiating an IV potassium infusion would be contraindicated in this situation as it would increase the already elevated potassium levels, potentially leading to dangerous cardiac complications.
Choice D rationale:
Encouraging the client to eat bananas is not advisable because bananas are high in potassium, which would exacerbate hyperkalemia.
Correct Answer is ["A","C","D"]
Explanation
A, C, and D.
Choice A rationale:
The administration of sodium bicarbonate helps to correct acidosis, which can occur in chronic renal failure due to the accumulation of metabolic waste products in the absence of effective kidney function.
Choice C rationale:
Sodium polystyrene sulfonate (Kayexalate) is used to treat hyperkalemia, which is common in chronic renal failure due to impaired potassium excretion by the kidneys.
Choice D rationale:
Insulin can be prescribed to treat hyperkalemia by promoting the uptake of potassium into cells, thereby reducing the serum potassium level. Choice B and E rationale: Dextrose 10% and furosemide (Lasix) are not appropriate treatments for hyperkalemia. Dextrose 10% is asugar solution and does not impact potassium levels, while furosemide is a loop diuretic that primarily affects sodium and water excretion, not potassium.
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