Exhibits
The nurse reviews the client data.
Drag the Word Choices to complete the sentence.
Abnormal FHR patterns can result in
The Correct Answer is {"dropdown-group-1":"D","dropdown-group-2":"E","dropdown-group-3":"E"}
Rationale for Correct Choices:
- Hypoxia: Abnormal fetal heart rate (FHR) patterns, especially decelerations, suggest that the fetus may not be receiving enough oxygen, leading to hypoxia. This condition requires prompt intervention to improve fetal oxygenation.
- Hypoxemia: Similar to hypoxia, hypoxemia refers to a low level of oxygen in the blood. If the abnormal FHR patterns continue, they may indicate that the fetus is not getting enough oxygen, leading to hypoxemia, which can result in further complications.
- Acidemia: A lack of oxygen (hypoxia and hypoxemia) can lead to acidemia, where there is an increase in the acidity of the fetal blood. This occurs when the fetus begins to build up metabolic acids, a sign of inadequate oxygenation and the body's inability to maintain proper pH balance.
Rationale for Incorrect Choices:
- Maternal hypotension: While maternal hypotension can affect fetal heart rate, it is not directly related to abnormal FHR patterns unless the hypotension is severe. The patient data provided does not indicate that maternal hypotension is the cause of the abnormal FHR pattern in this case.
- Hypoglycemia: While hypoglycemia can cause fetal distress, it is less likely to result in the specific FHR pattern here (decelerations). The cause of the decelerations appears to be more related to oxygenation issues rather than glucose imbalance.
- Meconium stool: Meconium passage can be a sign of fetal distress, but it is not a direct consequence of abnormal FHR patterns. The focus here is on the potential for oxygen deprivation and metabolic disturbances like acidemia and hypoxia.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is B
Explanation
A. Confer with the healthcare provider about a different course of antibiotics: While this may be necessary if treatment failure is confirmed, the first step is to evaluate whether the sexual partner was treated, as reinfection is common if the partner was not also treated.
B. Determine if the client's sexual partner received treatment for chlamydia: It is critical to ensure that the sexual partner has been treated for chlamydia as well. If the partner has not been treated, the client could have been reinfected, leading to ongoing symptoms despite completing the antibiotic regimen.
C. Inquire further about all sexual encounters and any other sexual activity: While understanding sexual history is important, the client explicitly stated she is maintaining a "monogamous relationship." the primary focus should be on ensuring that the partner was treated.
D. Ask the client if the complete course of antibiotics was completed: The client was treated with "azithromycin IM." Azithromycin for chlamydia is typically a single dose. The reinfection is more likely from an untreated partner, causing of the persistent symptoms.
Correct Answer is A
Explanation
A. One-hour glucose screen: The one-hour glucose screen is typically performed at 24-28 weeks gestation to screen for gestational diabetes. This is a standard test for all pregnant women during this time frame, regardless of ethnicity, and should be included in the client teaching.
B. Repeat HIV test: While HIV screening is important during pregnancy, a repeat HIV test at 28 weeks is not typically recommended for all women unless they are at high risk or have specific risk factors.
C. Multiple marker screening: This screening is usually done earlier in pregnancy, typically between 15-20 weeks, to assess the risk of certain fetal conditions like Down syndrome and neural tube defects. It is not performed at 28 weeks.
D. Direct Coombs' test: The Direct Coombs' test is typically performed on newborns, not on pregnant women, to check for hemolytic disease. However, Rh-negative women are often screened with the indirect Coombs' test at 28 weeks to check for antibodies, not the direct Coombs' test.
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