A bucket containing 2 4/5 gallons of water is 1/3 full. How many gallons of water is in one fully filled bucket?

To find the greatest number from the given options, we first convert the decimal numbers into fractions.

-0.7 becomes 7/10

-1.3 becomes 13/10

Then, we find the LCM for the denominators of the given fractions. The LCM of 3 and 10 is 30. Now we can multiply each fraction with the LCM.

-2/3*30=-20

-7/10*30=-70

-13/10*30=-39

-4/3*30=-40

Comparing the obtained values from above, -20 is the greatest followed by -39, -40, -70 in that order. The fraction -2/3 gave a value of -20, which was the greatest value. Thus, -2/3 is the greatest value from the given option.

By inspection, we find the corresponding values of the given denominations in the following manner.

Let x be the employee's salary before the raise. The employee received a 20% raise, so the new salary is:

x+0.2x=60,000

Step 1: Factor out x

1.2x=60,000

Step 2: Solve for x

x=60,000/1.2=50,000

We use the calculator to determine the positive square root of 20, which is then multiplied by 20.

Using the calculator,

Multiplying the square root above with 10 becomes

The approximate value is 44.7.

To calculate the percentage increase in client volume, use the formula:

PercentageIncrease×100

Step 1: Identify values

• Old Value (Year 1): 841 clients
• New Value (Year 2): 1,072 clients

Step 2: Compute the increase

1,072−841=231

Step 3: Calculate the percentage increase

×100 ≈ 27.47%

Step 4: Choose the closest answer

The closest option is 27%.

The mean of a data set is the total scores divided by the number of tests.

Total test scores =100+78+47+84+93+78=480

Number of tests =6

Mean test score =480/6=80

The mean test score is 80.

Percentages are fractions with denominator equal to 100. The given percent is divided by 100. To convert it to a decimal form, we move the decimal point two points to the left from the current position. Thus

The decimal form of 87.5% is 0.875.

To find the median, we arrange the following numbers in data set from the smallest to the largest as follows.

-3, -2, 0, 5, 10

From the above the data set, the median falls in the third position. Thus, 0 is the median for the given data set.

An independent variable is a variable that is manipulated or changed in the experiment. From the given equation, t is an independent variable, which when changed changes the values of the f(t).

We are asked to convert kg to pounds using the given relation. Letting x to represent the lb we are looking for.

Nest, we set the proportion with kg in the numerator and lb on the denominator as follows.

We find the value of x by cross-multiplication

The value of x is 110 lb.