**A child has a bottle full of pennies, nickels, dimes, and quarters. There are four as many quarters as pennies, two times as many as nickels as pennies, and seven times as many dimes as nickels. How many more dimes does the child have than nickels?**

7 times as many

5 times as many

2 times as many

10 times as many

*Correct Answer : A*

This problem asks us to compare the number of dimes to nickels.

If we let p be number of pennies in the bottle. Then,

Number of quarters in the bottle = 4p

Number of nickels in the bottle = 2p

Number of dimes in the bottle =7(2p)=14p

To find the number of dimes the child has than nickels, we use the ratio:

\(\frac{Dimes}{nickels} =\frac {14p}{2p}\ =\ 7\)

Thus, there are 7 times as many dimes as nickels in the box.

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