A child has collected 250 pennies, 200 nickels, 125 dimes, and 25 quarters. Which of the following charts accurately organizes the number of coins?
A
B
C
D
Correct Answer : A
In this scenario, we use the given chart and scale provided to find the number of each coin and select the right number of coins the student collected.
It is clear that the first choice if the correct answer. The child collected 250 pennies, 200 nickels, 125 dimes, and 25 quarters.
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Correct Answer is B
Explanation
To solve this problem, first find the radius of the circle.
Correct Answer is B
Explanation
 we are to find the selling price of the sweater from the marked price and the discount. The marked price is given as
Discount=mark off rate*original price
Discount=15%*$78
Convert 15% into a fraction, which become 15/100=0.15. Then
Discount=0.15*$78=$11.70
The selling price of the sweater will be the original price less the discount or mark off value. Then,
Thus, the approximate selling price of the sweater is $66.
Correct Answer is A
Explanation
The length of the unknown side of the rectangle can be found by using the Pythagoras theorem. Letting the unknown side to be x, the labelled rectangle becomes: The unknown length of the triangle is about 16.7 feet.
The length of the unknown side of the rectangle can be found by using the Pythagoras theorem. Letting the unknown side to be x, the labelled rectangle becomes:
The unknown length of the triangle is about 16.7 feet.
Correct Answer is A
Explanation
: We need to find the total rainfall for the months of May, June, and July using the given graph.
In the month of May, rainfall is between 3 and 4, which is halfway. Therefore, rainfall in May is 3.5 inches
On June, rainfall was 3 inch and on July the rainfall was 2.5 inches. Thus,
Total rainfall=3.5 inches+3 inches+ 2.5 inches=9.0 inches
Correct Answer is A
Explanation
To solve the equation this equation, we use a calculator and find the product as:
3.45 * 0.53= 1.8285
Correct Answer is B
Explanation
Histograms are used to present frequency of data of one variable over the other. On the other hand, a bar graph is used to compare the two variables with the rectangles not touching one another as in histograms. Scatter plots are used to show the correlations between two variables. In this case, the teacher will be able to use scatter plot to establish the correlation between test scores and the subjects.
Correct Answer is D
Explanation
From the given estimations, we can find the exact sum after adding the given numbers and see the trend the student utilizes to find their estimates. The actual sum is as follows
26+180=206
115+391=506
497+2024=2521
From the above evaluation, the students round the exact sum to the nearest tens. So, in the problem we need to approximate 545+7501.
545+7501=8046
The exact sum is 8046 and the approximate value after rounding to the nearest tens is 8050.
Correct Answer is C
Explanation
We usea calculator to find the product of
1.6*0.93=1.488
Correct Answer is C
Explanation
In this problem, we need to find the amount of gratuity the couple will leave. The gratuity is 16% of the total bill. Before solving the problem, the following are terms and their meaning in percent problems:
- Is means equals
- Of means multiply
- What means unknown (variable)
If we let x be the amount of gratuity, then translating the given problem into a mathematical equation becomes:
So, the value of x=9.376 and to the nearest cent, x=9.38
There, a couple will leave a gratuity of $9.38.
Correct Answer is A
Explanation
we are asked to find the largest value from the options given. To solve this problem, we need to convert all the given values into fraction. Then find the least common denominator for all fractions, which we will use to multiply each fraction and make a comparison.
43÷55=43/55
5/7
0.729=729/1000
73%=73/100
Now, we need to find the least common denominator of 55, 7, 1000, and 100, which is 77000. We multiply each fraction by 77000 as follows:
43/55*77000=60200
5/7*77000=55000
729/1000*77000=56133
73/100*77000=56210
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From the calculated values, it can be noted that 43/55 is the greatest value among the given options.
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