A farmer needs to buy fertilizer for his farmland. The instructions on the bag of the fertilizer say 49.5 pounds of fertilizer is needed for 1 acre of land. The farmer buys 2,000 pounds of fertilizer. Which of the following is the approximate number of acres he can cover with the fertilizer he bought?

The median temperature can be found by organizing the temperature values from the smallest to the largest value as follows:

98.6, 98.7, 99.0, 99.0,99.2, 99.3, 99.7, 100.0

(for an even set of numbers, Median = frac{(frac{n}{2})th observation + (frac{n}{2} + 1) th observation}{2})

From the data set above, there are 8temperature values. The median is the temperature value in the middle position, which falls between the(frac{n}{2} th)and((frac{n}{2} + 1) th) position. Here N=8and median is found as:

(frac{(frac{n}{2})th + (frac{n}{2} + 1) th}{2} = )(frac{(frac{8}{2})th + (frac{8}{2} + 1) th }{2} = 4.5th position)

The element in the 4.5th position is the average of the 4th and 5th element.

(frac{99.0 + 99.2}{2} = 99.1)

Thus 99.1 is the median temperature.

A whole pizza is equivalent to 1. Then

One friend eats half of the pizza=1/2 of 1=1/2*1=1/2

Remaining amount of pizza to be shared=1-1/2=2/2-1/2=1/2

Now, three friends share ½ equally and each friend will get,

Thus, the three friends each share 1/6.

We are given a mix of fractions and decimals and to compare the numbers, we convert the given decimals to fractions.

4.4 becomes 44/10

4.25 becomes 425/100

Now the set of fractions for comparison are: 9/2, 10/3, 44/10, and 425/100. The least common denominator for 2, 3 and 10 is 300. Then,

9/2*300=1350

10/3*300=1000

44/10*300=1320

425/10*300=1275

From the above products, 9/2 gives the greatest value when the fractions are compared with the least common denominator of the given denominators.

The best way to display the frequency of each day of the week when students get up after 8 a.m. is by using a bar graph. Bar graphs are well-suited for representing categorical data, where each day of the week is a separate category, and the height of each bar corresponds to the count or frequency of students waking up late on that specific day.

Note: Histograms, on the other hand, are more appropriate for visualizing continuous or numerical data and are not ideal for categorical data like days of the week.Histograms are useful for understanding the distribution of data, identifying patterns, and assessing the shape of the data distribution, such as whether it's normally distributed, skewed, or has multiple modes.

As you can see below, the Histogram is used to depict a pattern/continuous data. While a bar graph does just fine even with discrete data.

In the simple interest, we utilize the following formula to find the simple interest after a period of time in years.

I=P*r*t

I is the interest

P=Principal or initial deposit

r=rate

t=time in years

From the given problem, P=$600, r=6%=6/100=0.06, t=5 years. Then

I=$600*0.06*5=$180

After 5 years, Pat will earn an interest of $180.

We extrapolate the values of a line between 10 and 15 on y-axis to meet the curve and drop another line from the intersection of the curve to meet the x-axis and read off the age of the car.

Now, let’s extrapolate in the following diagram

The intersection of the line and the x-axis is between 4 and 5 years. This means that the car is about 4.5 years old. From the options given, the age of the car is more than 3 years old.

Here we collect like terms together and solve for the unknown value of x.

7x-6=3x-26

Add 6 to both sides of the equation

7x-6+6=3x-26+6

7x=3x-20

Subtract 3x from both sides of the equation

7x-3x=-20

4x=-20

Divide both sides by 4

4x/-4=-20/4

x = -5

The value of x = -5

To answer this question, we need to observe the trend of the number of days with dollars. On day 2, the dollars were 8, after 5 days, the dollars decreased to 3, after 13 days, the dollars increased to 10. After 14 days, the dollars declined to 6 and again rose to 16 dollars after 19 days.

From this observation, we cannot be able to establishany correlation between days and dollars.

all products represent 100%. Then, the portion of defect products is:

0.0025 of 100%

‘of’ means multiply

0.0025 *100%=0.25%

Let xxx be the amount the friend paid for their car. The problem states:

48,000=2x−2,000

Step 1: Solve for x

Add 2,000 to both sides:

48,000+2,000=2x

Divide by 2:

x=25,000