A patient drives 19 miles one way to a medical facility for treatment. How far does the patient drive round-trip in 22 days of treatment?
1,254 miles
1,672 miles
418 miles
836 miles
Correct Answer : D
Round trip means to and from, which is twice the distance from home to a medical facility.
In one day, the round trip=19+19=38 miles
So, in 22 days, the round trip=38*22=836 miles.
The patient will cover 836 miles in 22 days.
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Correct Answer is D
Explanation
we use the US customary system of units’ equivalent to convert from yards to inches. We know that 1yard=3 ft, and 1 ft =12 inches.
First, convert 2 ¾ into an improper fraction.
Then,
Correct Answer is B
Explanation
The median temperature can be found by organizing the temperature values from the smallest to the largest value as follows:
98.6, 98.7, 99.0, 99.0,99.2, 99.3, 99.7, 100.0
(for an even set of numbers, Median = frac{(frac{n}{2})th observation + (frac{n}{2} + 1) th observation}{2})
From the data set above, there are 8temperature values. The median is the temperature value in the middle position, which falls between the(frac{n}{2} th)and((frac{n}{2} + 1) th) position. Here N=8and median is found as:
(frac{(frac{n}{2})th + (frac{n}{2} + 1) th}{2} = )(frac{(frac{8}{2})th + (frac{8}{2} + 1) th }{2} = 4.5th position)
The element in the 4.5th position is the average of the 4th and 5th element.
(frac{99.0 + 99.2}{2} = 99.1)
Thus 99.1 is the median temperature.
Correct Answer is A
Explanation
From the given problem,
49.5 pounds of fertilizer is needed to farm 1 acre of land. This can be interpreted as:
Or
Now we are needed to find the acres of land that will be farmed using 2000 pounds of fertilizers. To solve this, we use the second option as follows:
2000 pounds of fertilizers can farm approximately 40 acres of land.
Correct Answer is B
Explanation
from the provided table, the first option represents the amount of gas in gallons while the second column shows the distance in miles. Thus, (6, 144) will denote that the car can 144 miles by consuming 6 gallons of a gas.
Correct Answer is A
Explanation
Here we collect like terms together and solve for the unknown value of x.
7x-6=3x-26
Add 6 to both sides of the equation
7x-6+6=3x-26+6
7x=3x-20
Subtract 3x from both sides of the equation
7x-3x=-20
4x=-20
Divide both sides by 4
4x/-4=-20/4
x = -5
The value of x = -5
Correct Answer is A
Explanation
We need to find the length of the rectangle from the given area and width of the rectangle. Let L be length if the rectangle. Then,
Area of rectangle=Length*width
Substituting area=32 in2 and w=4 inches
32=L*4
32=4L
Divide both sides by 4
32/4=4L/4
8=L
The length of the rectangle is 8 inches.
Correct Answer is A
Explanation
We are given a mix of fractions and decimals and to compare the numbers, we convert the given decimals to fractions.
4.4 becomes 44/10
4.25 becomes 425/100
Now the set of fractions for comparison are: 9/2, 10/3, 44/10, and 425/100. The least common denominator for 2, 3 and 10 is 300. Then,
9/2*300=1350
10/3*300=1000
44/10*300=1320
425/10*300=1275
From the above products, 9/2 gives the greatest value when the fractions are compared with the least common denominator of the given denominators.
Correct Answer is A
Explanation
all products represent 100%. Then, the portion of defect products is:
0.0025 of 100%
‘of’ means multiply
0.0025 *100%=0.25%
Correct Answer is B
Explanation
From the given scenario:
Initial charge is $40
Additional charge per circular cloth=$5c
Additional charge per rectangular cloth=$3.50r
Total cost = additional charge per circular rectangular cloths + Initial charge
Total cost, T = 5c + 3.5r + 40
Correct Answer is C
Explanation
We extrapolate the values of a line between 10 and 15 on y-axis to meet the curve and drop another line from the intersection of the curve to meet the x-axis and read off the age of the car.
Now, let’s extrapolate in the following diagram
The intersection of the line and the x-axis is between 4 and 5 years. This means that the car is about 4.5 years old. From the options given, the age of the car is more than 3 years old.
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