A survey of 500 teenagers was taken to see which sport was the favorite to watch on television. The pie chart above represents the results. Which of the following data sets (number of teenagers) was used to develop the pie chart?

from the provided table, the first option represents the amount of gas in gallons while the second column shows the distance in miles. Thus, (6, 144) will denote that the car can 144 miles by consuming 6 gallons of a gas.

To answer this question, we need to observe the trend of the number of days with dollars. On day 2, the dollars were 8, after 5 days, the dollars decreased to 3, after 13 days, the dollars increased to 10. After 14 days, the dollars declined to 6 and again rose to 16 dollars after 19 days.

From this observation, we cannot be able to establishany correlation between days and dollars.

From the given scenario:

Initial charge is $40

Additional charge per circular cloth=$5c

Additional charge per rectangular cloth=$3.50r

Total cost = additional charge per circular rectangular cloths + Initial charge

Total cost, T = 5c + 3.5r + 40

We can interpret ‘cannot exceed” as less than ‘<’. Therefore, in our inequality, the symbol < must be included. Now let’s convert the word problem into a mathematical inequality.

Money spent on supplies=s

Money spent on textbooks=t

Total money spent=money spent on supplies + money spent on textbooks

Total money spent = s+t

But the money spent cannot exceed $12,000. Then,

s+t <$12,000.
However the money spent can still be equal to $12000, as it has not exceeded it.

Therefore, therequired inequality is s + t <= $12,000.

The best way to display the frequency of each day of the week when students get up after 8 a.m. is by using a bar graph. Bar graphs are well-suited for representing categorical data, where each day of the week is a separate category, and the height of each bar corresponds to the count or frequency of students waking up late on that specific day.

Note: Histograms, on the other hand, are more appropriate for visualizing continuous or numerical data and are not ideal for categorical data like days of the week.Histograms are useful for understanding the distribution of data, identifying patterns, and assessing the shape of the data distribution, such as whether it's normally distributed, skewed, or has multiple modes.

As you can see below, the Histogram is used to depict a pattern/continuous data. While a bar graph does just fine even with discrete data.

We need to find the length of the rectangle from the given area and width of the rectangle. Let L be length if the rectangle. Then,

Area of rectangle=Length*width

Substituting area=32 in2 and w=4 inches

32=L*4

32=4L

Divide both sides by 4

32/4=4L/4

8=L

The length of the rectangle is 8 inches.

Here we collect like terms together and solve for the unknown value of x.

7x-6=3x-26

Add 6 to both sides of the equation

7x-6+6=3x-26+6

7x=3x-20

Subtract 3x from both sides of the equation

7x-3x=-20

4x=-20

Divide both sides by 4

4x/-4=-20/4

x = -5

The value of x = -5

In this problem, we take the triangle as a right-angled triangle and label it as follows:

From the Pythagoras theorem A2 + B2= C2, we can look for a combination of A and B that when the squares of A and B are summed give a square of 13.  Mathematically,

But C=13 inches

If we take A=5 inches and B=12 inches, then

Next, we take A=2.5 inches, B=6 inches

Next, we take A=2.5 inches, B=4 inches

6.25+16=169

22.25≠169

Taking A=5 inches and B=8 inches

From the above computation, the combination of A=5 inches and B=12 inches give a triangle with a hypothenuse of 13 inches.

We convert the given weight in pounds to ounces and find total weight. 1 pound=16 ounces, which we interpret as

Or

Use the second option to convert pounds to ounces

Now, we can ounces to ounces as: 48 oz + 5 oz= 53 oz

Therefore, 3 pounds, 5 ounces is equal to 53 oz

In the simple interest, we utilize the following formula to find the simple interest after a period of time in years.

I=P*r*t

I is the interest

P=Principal or initial deposit

r=rate

t=time in years

From the given problem, P=$600, r=6%=6/100=0.06, t=5 years. Then

I=$600*0.06*5=$180

After 5 years, Pat will earn an interest of $180.