A survey of 500 teenagers was taken to see which sport was the favorite to watch on television. The pie chart above represents the results. Which of the following data sets (number of teenagers) was used to develop the pie chart?

The whole pie chart represents 100%, which we use together with the given percentages to find the respective different sports. Note that 100% is equal to 500 surveyed students. The, the number of teenagers who prefer:

Soccer

Hockey

Football

Basketball

Other

From the evaluations above, 90 teenagers love soccer, 80 love hockey, 190 teenagers love football, 120 teenagers love basketball, and 20 teenagers love others.

from the provided table, the first option represents the amount of gas in gallons while the second column shows the distance in miles. Thus, (6, 144) will denote that the car can 144 miles by consuming 6 gallons of a gas.

Percentages always add up to 100%. If we let x be the percent of graduates working for jobs unrelated to law, then

74%+3%+2%+x=100%

79%+x=100%

Subtract 79% from both sides of the equation

79%-79%+x=100%

x=100%-79%

x=21%

So, the number of graduates working for jobs unrelated to law is 21%.

We convert the given weight in pounds to ounces and find total weight. 1 pound=16 ounces, which we interpret as

Or

Use the second option to convert pounds to ounces

Now, we can ounces to ounces as: 48 oz + 5 oz= 53 oz

Therefore, 3 pounds, 5 ounces is equal to 53 oz

to do a comparison of the given data set, we convert the fraction numbers into the approximate decimals.

4/3=1.333

2720=1.35

Now, we have 1.333, 1.35, 1.369, 1.357. These numbers are arranged from the smallest to the largest number, we look at the number in the second decimal place value

1.333 the number in second decimal place value is 3

1.35 the number in third decimal place value is 5

1.369 the number in third decimal place value is 6

1.357 the number in third decimal place value is 5

However, 1.35 and 1.357 have 5 in the second-place vale. We use the ird place value to compare the two number:

1.35 is same as 1.350 and the number in the third-place value is 0

1.357 the number in the third-place value is 7

Now, 0 is less than 7, and thus 1.35 is less than 1.357

Overall, 3 is less than 5, and 5 less than 6 and the provided numbers can be arranged from the smallest to the largest as:

1.333, 1.35, 1.357, 1.369

Thus, the corresponding given numbers organized from the smallest to the largest become:

4/3, 27/20, 1.357, 1.369

The greatest value is 1.369

Here we are required to find the area of the square of sides 3.1 m. The square is a four-sided figure with each side equal and opposite sides making 90 degrees.

Area of the square =side*side

Side=3.1 m

Area of the square =3.1 m *3.1 m=9.61 m2

Note: 3.1 + 3.1 = 6.2 which is a wrong answer.

we are asked to change 400 mg to g. We use the conversion 1g=1000mg, which we can write as:

So, 400 mg to g becomes

Here we collect like terms together and solve for the unknown value of x.

7x-6=3x-26

Add 6 to both sides of the equation

7x-6+6=3x-26+6

7x=3x-20

Subtract 3x from both sides of the equation

7x-3x=-20

4x=-20

Divide both sides by 4

4x/-4=-20/4

x = -5

The value of x = -5

The median temperature can be found by organizing the temperature values from the smallest to the largest value as follows:

98.6, 98.7, 99.0, 99.0,99.2, 99.3, 99.7, 100.0

(for an even set of numbers, Median = frac{(frac{n}{2})th observation + (frac{n}{2} + 1) th observation}{2})

From the data set above, there are 8temperature values. The median is the temperature value in the middle position, which falls between the(frac{n}{2} th)and((frac{n}{2} + 1) th) position. Here N=8and median is found as:

(frac{(frac{n}{2})th + (frac{n}{2} + 1) th}{2} = )(frac{(frac{8}{2})th + (frac{8}{2} + 1) th }{2} = 4.5th position)

The element in the 4.5th position is the average of the 4th and 5th element.

(frac{99.0 + 99.2}{2} = 99.1)

Thus 99.1 is the median temperature.

We are given that 1 teaspoon=4.93 mL, we can interpret it as:

Or

Since we are to find the amount in mL, we look for an option that will cancel teaspoon and remain with mL. The second option is the required conversion, and we proceed as follows:

Therefore, 2.5 teaspoons hold about 12.325 mL.