A teacher has asked all the students in the class which data visualizer he will use to show relationship between their scores and number of subjects. Which of the following is the best way to display the frequency of each day of the week?

Before we compare the values of the options, we convert the decimals to fractions.

5.4 becomes 54/10

6.25 becomes 625/100

Thus, the set of fractions is 11/2, 54/10, 13/3, 625/100. The least common denominator for 2, 10, 3, and 100 is 300, which we use to compare each options given.

11/2*300=1650

54/10*300=1620

13/3*300=1300

625/100*300=1875

From the above, 1875 is the greatest value which corresponds to 6.25. Therefore, 6.25 is the greatest value of all the choices given.

From the given estimations, we can find the exact sum after adding the given numbers and see the trend the student utilizes to find their estimates. The actual sum is as follows

26+180=206

115+391=506

497+2024=2521

From the above evaluation, the students round the exact sum to the nearest tens. So, in the problem we need to approximate 545+7501.

545+7501=8046

The exact sum is 8046 and the approximate value after rounding to the nearest tens is 8050.

we are asked to find the largest value from the options given. To solve this problem, we need to convert all the given values into fraction. Then find the least common denominator for all fractions, which we will use to multiply each fraction and make a comparison.

43÷55=43/55

5/7

0.729=729/1000

73%=73/100

Now, we need to find the least common denominator of 55, 7, 1000, and 100, which is 77000. We multiply each fraction by 77000 as follows:

43/55*77000=60200

5/7*77000=55000

729/1000*77000=56133

73/100*77000=56210

From the calculated values, it can be noted that 43/55 is the greatest value among the given options.

To solve the equation this equation, we use a calculator and find the product as:

3.45 * 0.53= 1.8285

: we are needed to find the portion of burger the two other friends share between themselves. A whole burger is 1, and we know that,

One friend=1/4 of 1=1/4*1=1/4

Remaining amount=1-1/4=4/4-1/4=3/4

Thus, ¾ of burger is left for two friends to share among themselves. Then, each friend will get

So, the other two friends will each get 3/8 of the burger.

We are needed to find the amount Jacob will be left with after spending and reinvesting the rest using the given information.

Amount Jacob spends=87% of $100=87/100*100=$87

Amount left to invest=$(100-87)=$13

Jacob is left with $13, which she invests and earns a profit of 75%.

Profit earned on invested amount=75% of $13=75/100*13=$9.75

So, Jacob will have $13+$9.75=$22.75

: the question requires we find the cost of four syringes.

If we let x be the cost of four syringes, then we set up a proportion equation with cost as numerator and number of syringes as denominator. The proportion equation becomes

Cross-multiply to solve for x

Rearranging the above

Divide both sides of the equation by 55

Thus, the cost of 4 syringes is $48.

Correlation of two variables falls into:

Positive correlation: an increase in one variable causes another variable to increase

Negative correlation: an increase in one variable causes another one to decrease

No correlation: a change in one variable does not cause any response in another variable.

From the given choices

Option a is no correlation

Option b is a negative correlation

Option c is a negative correlation

Option d is a positive correlation

Thus, the correct statement is a.

: In order to solve for the value of x, we use the order of operations as follows:

The first step is to divide both sides by 3

Add 2 to both sides to eliminate it from the left-hand side of the equation

x-2+2=4+2

x = 6

Thus, the value of x is 6.

from the given data, one gallon of cleaning solution requires 6 oz of ammonia. The mathematical expression of this statement can be expressed in two ways:

Or

The question requires we find the amount of ammonia needed to make 230 gallons of the solution. So, we use the second option and proceed as follows:

From the above equation, gallon of solution will cancel, and oz of ammonia is left.

Therefore, the solution will require 1380 oz of ammonia.