As a person cycling increases speed, the rate of calories burned, distance traveled, and energy expended also increase. Which of the following is the independent variable?

To find the least common denominator (LCD) of the fractions 1/2, 2/3, and 4/5, follow these steps:

Step 1: Identify the denominators

The denominators are 2, 3, and 5.

Step 2: Find the least common multiple (LCM)

The LCM of 2, 3, and 5 is the smallest number that all three denominators divide into evenly.

• Prime factorization:
  • 2=2
  • 3=3
  • 5=5

Since 2, 3, and 5 are all prime numbers, their LCM is:

2×3×5=30

The best way to display the frequency of each day of the week when students get up after 8 a.m. is by using a bar graph. Bar graphs are well-suited for representing categorical data, where each day of the week is a separate category, and the height of each bar corresponds to the count or frequency of students waking up late on that specific day.

Note: Histograms, on the other hand, are more appropriate for visualizing continuous or numerical data and are not ideal for categorical data like days of the week.Histograms are useful for understanding the distribution of data, identifying patterns, and assessing the shape of the data distribution, such as whether it's normally distributed, skewed, or has multiple modes.

As you can see below, the Histogram is used to depict a pattern/continuous/rangedata. While a bar graph does just fine even with discrete data.

To simplify the expression:

12+3×4−1+23

Step 1: Follow the order of operations (BODMAS)

Multiplication first:

3×4=12

23 = 2×2×2=8

Now the expression becomes:

12+12−1+8

Step 2: Perform addition and subtraction from left to right

• 12+12=24
• 24−1=23
• 23+8=31

The correct answer is 31.

The initial step is to convert the decimal numbers into fractions.

4.4 becomes 44/10

4.25 becomes 425/100

Thus, the set of fractions is 9/2, 44/10, 10/3, 425/100. The least common denominator for 2, 10, 3, and 100 is 300, which we use to compare each options given.

9/2*300=1350

44/10*300=1320

10/3*300=1000

425/100*300=1275

From the above, 1350 is the greatest value which corresponds to 9/2. Thus, 9/2 is the greatest value of all the choices given.

to change L to mL we use the following options of interconversions:

Or

Since we are needed to change L to mL, use the second option.

Thus, a bucket can hold 3000 mL which is equal to 3 L.

we follow the order operations to solve for the unknown value of x.

2(4x+3)=7x+5

Open the bracket on the LHS by multiplying each term by 2

(2*4x)+(2*3)=7x+5

8x+6=7x+5

Subtract 6 from both sides

8x+6-6=7x+5-6

8x=7x-1

Subtract 7x on both sides

8x-7x=7x-7x-1

X=-1

Thus, the value of unknown value of x is -1.

we need to find the net income of the nurse in 4 weeks from the weekly net income.

Weekly net income=gross income-total tax

Total tax=federal income tax+state income tax+Social Security tax

Total tax=$(83.00+38.00+79.00)

Total tax=$200.00

Weekly net income=$(800.00-200.00)=$600.00

In one week, the net income of the nurse is $600.00 and in 4 weeks the nurse will a net income of:

The nurse will earn $2,400.00 in 4 weeks after taxes are deducted.

We need to find how many mL are in 2.5 teaspoons. We need to use dimensional analysis to solve this problem as follows.

Converting between teaspoon and mL uses the following conversions:

Or

We want to end up with mL, we utilize the second conversion and set up the following equation.

Thus, 2.5 teaspoons can hold 12.325 mL.

In this scenario, we use the given scale in the charts to find the number of each coin and selected the right number of coins the student collected. The second options shows that the child collected 50 pennies, 45 nickels, 25 dimes, and 5 quarters.

we use given information to find how much ammonia is need to make the specified solution.

We are told, one gallon of cleaning solution requires 6 oz of ammonia. In other words, we can express this as:

1 gallon of solution6 oz of ammonia

Or

6 oz of ammonia1 gallon of solution

Since we are needed to find how much ammonia is needed, we use the second option to find how much ammonia is required by 120 gallons of solution.

From the above equation, gallon of solution will cancel, and oz of ammonia is left.

Therefore, the solution will require 720 oz of ammonia.