The amount of salary a technician takes home in a month increases with sales of stocks, the amount of charge fees, and the number of working hours. Which of the following is the dependent variable?

By inspection, we find the corresponding values of the given denominations in the following manner.

we use the relation 1 L=1000 mL and organize our equation in such a way that L cancels as:

Thus, 0.65 L is 650 mL.

To simplify this expression, we follow the order of operations as follows:

First, we start with the numerator and solve it as follows

[2(6+3*9)]

We start with multiplication in inner brackets, 3 * 9 = 27. The expression becomes

[2(6+27)]

Then, we carry out the addition of 6+27=33. Then, the expression yields

[2(33)]=2*33=66

Now, we solve for denominator, which is 6/2=3.

Thus, the expression is reduced into

The expression reduces into 22.

A dependent variable is one that changes when another variable changes. In this case, the cost of the phone will change depending on the change inbrand name, size of the RAM, and size of the battery. Thus, cost of a phone is a dependent variable.

The slope represents the ratio of rise to run. Let p be the minimum length of the ramp, we can set a ratio equation as follows. Then,

The minimum length of the ramp needed is 18 feet to access to a door that is 1.5 feet above the sidewalk.

An independent variable is a variable that is manipulated or changed in the experiment. From the given equation, x is variable that is changed to obtain the desired outcome, F(x). Therefore, x is an independent variable.

We are given the equation:

6x−5=10x+15

Step 1: Move all xxx-terms to one side

Subtract 6x from both sides:

−5=10x−6x+15

Step 2: Move constants to the other side

Subtract 15 from both sides:

−5−15=4x

−20=4x

Step 3: Solve for x

Divide both sides by 4:

x=−20/4 = −5

9/20 is the same as 9 divided by 20, which is evaluated 9÷20. The value becomes 0.45.

Thus, 9/20 is equal to 0.45.

we are asked to find the amount of milk in mL using the given information.

If we let x represent the amount of milk in mL, we set up a proportion with number of teaspoons on the numerator and amount in mL in the denominator.

A recipe of 3.4 teaspoons is equal to 17.0 mL.

in this case, we express James’ uncle’s age in terms of James’ age. From the equation:

James’ age is n

James’s uncle’s age is m=3n-13

Thus, the relation that relates James’ uncle’s age in terms of James’ age is m=3n-13.