How many milliliters are there in 3.9 liters?

To find the required number of cups milk needed, we set a proportion equation with number of cups be numerator and cups of milk as denominator.

Let x be the number of cups of milk needed, then

The numbers of cups of milk required is 273/25, which when converted to mixed fraction becomes 10 23/25.

The range is a simple measure of statistical dispersion that shows the spread between the highest and lowest values in a data set.

Formula for Range:

Range=MaximumValue−MinimumValue

Example Calculation:

From the given box plot:
Identify the maximum value: 92

1. Identify the minimum value: 12
2. Subtract the minimum from the maximum: 92−12=80

Thus, the range of this data set is 80.

we find the value of x by applying the absolute conditions to the given equation.

First, add 2 to both sides of equation

Add 10 to both sides of the equation

Next, we apply the absolute rule:

If u=a, a>0, then u=a or u=-a

In this case a=5, which is greater 0.

The first condition becomes

Solving for x

The second condition becomes

Solving for x

Then, the value of x is -4/3 or 2.

we are asked to find the number of students enrolled in the nursing program using the percentages in the pie chart.

If we let x represent the number of students enrolled in the nursing program, we set a proportion equation with number of students on the numerator and percentages on the denominator.

Total percent in the pie chart is 100%, which equals 800 students. Then, 42% will represent

We solve the value of x by cross-multiplying the equation above.

Therefore, 336 students will enroll for a nursing program.

A standard six-sided die has the numbers 1, 2, 3, 4, 5, and 6. The even numbers are 2, 4, and 6.

Step 1: Probability of rolling an even number on the first roll

There are 3 even numbers out of 6 total numbers, so:

P (evenonsecondroll) = 3/6 = ½

Step 2: Probability of rolling an even number on the second roll

Since rolling the die is an independent event, the probability remains:

P (evenonsecondroll) = 3/6 = ½

Step 3: Multiply the probabilities

P (evenonfirstANDevenonsecond) = ½ × ½ = ¼

The range of a data set is calculated as:

Range=MaximumValue−MinimumValue

From the given bar graph:

• The minimum number of goals scored is 0.
• The maximum number of goals scored is 5.

Thus, the range is:

5−0=5

We follow the order of operations to solve the given expression.

First, we start with the numerator and solve it as follows

[3(2+6*4)]

We start with multiplication in inner brackets, 6*4=24. The expression becomes

[3(2+24)]

Then, we conduct the addition of 2+24=26. Then, the expression becomes

[3(26)]=3*26=78

Now, we solve for denominator, which is 26/2=13.

Thus, the expression is reduced into

\(\frac{[3(2+6\ast4)]}{(26\div2)}=\frac{78}{13}=6\)

The expression reduces into 6.

 We are asked to make w the subject of the formula.

First, we rearrange the equation by to ensure w is on the right hand of the equation.

Then, divide both sides by r

Multiply both sides by y

The above equation can be rearranged into

Thus, the formula for finding the value of w is (x/ry)-(z/r).

The initial step is to convert the decimal options to fractions. Then, we find the LCM of the denominators of all fractions, which will be used to compare the values of the given options.

-0. becomes -9/10

-1.7 becomes -17/10

Then, the resulting denominators are 9, 10, and 63. Their LCM of 630 is used to multiply each fraction.

-2/9*630=-140

-9/10*630=-567

-17/10*630=-1071

-4/7*630=-360

From the calculations above, -140 is the greatest value of all the values. Thus, -2/9 is the greatest number.

A dependent variable changes with any change made in an independent variable. From this case, cost of meals depends on other three options. In other words, the quantity of meal, number of toppings, and types of spices influence the cost of the meal.