Pat deposits $600 in a savings account at a simple interest rate 6% per year for 5 years. How much money will Pat have earned in interest at the end of 5 years?

Here we are required to find the area of the square of sides 3.1 m. The square is a four-sided figure with each side equal and opposite sides making 90 degrees.

Area of the square =side*side

Side=3.1 m

Area of the square =3.1 m *3.1 m=9.61 m2

Note: 3.1 + 3.1 = 6.2 which is a wrong answer.

Here we collect like terms together and solve for the unknown value of x.

7x-6=3x-26

Add 6 to both sides of the equation

7x-6+6=3x-26+6

7x=3x-20

Subtract 3x from both sides of the equation

7x-3x=-20

4x=-20

Divide both sides by 4

4x/-4=-20/4

x = -5

The value of x = -5

to do a comparison of the given data set, we convert the fraction numbers into the approximate decimals.

4/3=1.333

2720=1.35

Now, we have 1.333, 1.35, 1.369, 1.357. These numbers are arranged from the smallest to the largest number, we look at the number in the second decimal place value

1.333 the number in second decimal place value is 3

1.35 the number in third decimal place value is 5

1.369 the number in third decimal place value is 6

1.357 the number in third decimal place value is 5

However, 1.35 and 1.357 have 5 in the second-place vale. We use the ird place value to compare the two number:

1.35 is same as 1.350 and the number in the third-place value is 0

1.357 the number in the third-place value is 7

Now, 0 is less than 7, and thus 1.35 is less than 1.357

Overall, 3 is less than 5, and 5 less than 6 and the provided numbers can be arranged from the smallest to the largest as:

1.333, 1.35, 1.357, 1.369

Thus, the corresponding given numbers organized from the smallest to the largest become:

4/3, 27/20, 1.357, 1.369

The greatest value is 1.369

to solve for x, we order like terms together and proceed as follows:

4x-3-5x=24

Add 3 to both sides of the equation

4x-3+3-5x=24+3

4x+3-3-5x=27

4x-5x=27

-x=27

Divide both sides by -1

-x/-1=27/-1

x= -27

Thus, the unknown value of x is -27

The best way to display the frequency of each day of the week when students get up after 8 a.m. is by using a bar graph. Bar graphs are well-suited for representing categorical data, where each day of the week is a separate category, and the height of each bar corresponds to the count or frequency of students waking up late on that specific day.

Note: Histograms, on the other hand, are more appropriate for visualizing continuous or numerical data and are not ideal for categorical data like days of the week.Histograms are useful for understanding the distribution of data, identifying patterns, and assessing the shape of the data distribution, such as whether it's normally distributed, skewed, or has multiple modes.

As you can see below, the Histogram is used to depict a pattern/continuous data. While a bar graph does just fine even with discrete data.

We can interpret ‘cannot exceed” as less than ‘<’. Therefore, in our inequality, the symbol < must be included. Now let’s convert the word problem into a mathematical inequality.

Money spent on supplies=s

Money spent on textbooks=t

Total money spent=money spent on supplies + money spent on textbooks

Total money spent = s+t

But the money spent cannot exceed $12,000. Then,

s+t <$12,000.
However the money spent can still be equal to $12000, as it has not exceeded it.

Therefore, therequired inequality is s + t <= $12,000.

In the simple interest, we utilize the following formula to find the simple interest after a period of time in years.

I=P*r*t

I is the interest

P=Principal or initial deposit

r=rate

t=time in years

From the given problem, P=$600, r=6%=6/100=0.06, t=5 years. Then

I=$600*0.06*5=$180

After 5 years, Pat will earn an interest of $180.

We are given a mix of fractions and decimals and to compare the numbers, we convert the given decimals to fractions.

4.4 becomes 44/10

4.25 becomes 425/100

Now the set of fractions for comparison are: 9/2, 10/3, 44/10, and 425/100. The least common denominator for 2, 3 and 10 is 300. Then,

9/2*300=1350

10/3*300=1000

44/10*300=1320

425/10*300=1275

From the above products, 9/2 gives the greatest value when the fractions are compared with the least common denominator of the given denominators.

We need to find the length of the rectangle from the given area and width of the rectangle. Let L be length if the rectangle. Then,

Area of rectangle=Length*width

Substituting area=32 in2 and w=4 inches

32=L*4

32=4L

Divide both sides by 4

32/4=4L/4

8=L

The length of the rectangle is 8 inches.

total muffin is equal to the sum of the different muffins sold.

Total muffins=41+27+20=88 muffins

Thus, the bakery sold about 90 muffins.