2.50*0.25

Simplify the expression above. Which of the following is correct?

The first three months of the year are January, February, and March. We need to find the total rainfall for these three months from the provided graph.

In the month of January, rainfall is between o and 1, which is halfway. Therefore, rainfall in January is 0.5 inches

On February, rainfall was 1 inch and on March the rainfall was 2 inches. Thus,

Total rainfall = 0.5 inches + 1 inches + 2 inches = 3.5 inches

we need to find the net income of the nurse in 4 weeks from the weekly net income.

Weekly net income=gross income-total tax

Total tax=federal income tax+state income tax+Social Security tax

Total tax=$(83.00+38.00+79.00)

Total tax=$200.00

Weekly net income=$(800.00-200.00)=$600.00

In one week, the net income of the nurse is $600.00 and in 4 weeks the nurse will a net income of:

The nurse will earn $2,400.00 in 4 weeks after taxes are deducted.

We need to find how many mL are in 2.5 teaspoons. We need to use dimensional analysis to solve this problem as follows.

Converting between teaspoon and mL uses the following conversions:

Or

We want to end up with mL, we utilize the second conversion and set up the following equation.

Thus, 2.5 teaspoons can hold 12.325 mL.

scatter plots can of three types: positive, negative and no correlation. A positive correlation scatter plot shows that as one variable increase, the other variable increases. A positive correlation can be visually depicted below.

In a negative correlation, the change in one variable is inversely proportional to another variable. That is, as one variable increases, the other variable decreases as shown below.

The third type of scatter plot is a no-correlation scatter plot. In this type of plot, there is no defined relationship between one variable and another one as in the curve below.

If we look at the relationship between the time the student listens to music and his test score, it is evident that no relationship exists between the two variables. Thus, this is a type of no correlation scatter plot.

in the given problem, we use the calculator to find 1.3*0.47=0.611

we use given information to find how much ammonia is need to make the specified solution.

We are told, one gallon of cleaning solution requires 6 oz of ammonia. In other words, we can express this as:

1 gallon of solution6 oz of ammonia

Or

6 oz of ammonia1 gallon of solution

Since we are needed to find how much ammonia is needed, we use the second option to find how much ammonia is required by 120 gallons of solution.

From the above equation, gallon of solution will cancel, and oz of ammonia is left.

Therefore, the solution will require 720 oz of ammonia.

To find the least common denominator (LCD) of the fractions 1/2, 2/3, and 4/5, follow these steps:

Step 1: Identify the denominators

The denominators are 2, 3, and 5.

Step 2: Find the least common multiple (LCM)

The LCM of 2, 3, and 5 is the smallest number that all three denominators divide into evenly.

• Prime factorization:
  • 2=2
  • 3=3
  • 5=5

Since 2, 3, and 5 are all prime numbers, their LCM is:

2×3×5=30

here we use the US customary system to convert between yards and feet. We use the conversion 1 yard =3 feet. Then, 6 yards to ft is found as

Thus, 6 yards is equal to 18 ft.

The length of the unknown side of the rectangle can be found by using the Pythagoras theorem. We label the triangle from the given data as shown below

Let the unknown length be x.

Applying the Pythagoras theorem, the value of x is found as:

\(a ^2 +b ^2 =c ^2\)

The unknown length of the triangle is approximately 8.9 feet.

The best way to display the frequency of each day of the week when students get up after 8 a.m. is by using a bar graph. Bar graphs are well-suited for representing categorical data, where each day of the week is a separate category, and the height of each bar corresponds to the count or frequency of students waking up late on that specific day.

Note: Histograms, on the other hand, are more appropriate for visualizing continuous or numerical data and are not ideal for categorical data like days of the week.Histograms are useful for understanding the distribution of data, identifying patterns, and assessing the shape of the data distribution, such as whether it's normally distributed, skewed, or has multiple modes.

As you can see below, the Histogram is used to depict a pattern/continuous/rangedata. While a bar graph does just fine even with discrete data.