The force applied is directly proportional to the stretch of a coil. If a force of 132 Newtons stretches a coil 0.07 meters, what force would be needed to stretch a coil 0.1 meter? Round your answer to the nearest tenth.

Yoghurt: toppings=4:3

Yoghurt: 4.5 oz =4:3

We convert the given ratio into a proportion equation as below

Multiply both sides by 4.5 oz

Standard interior doors typically range from0.7 to 0.9 metersin width and 2.0 to 2.1 meters in height. Thus, the average width of the doorway is about 1.0 m.

In direct proportion relation, we utilize the relationship as:

Variable∝Variable 2

Thus from the given case,

Force∝stretch

We introduce a constant term, K to remove the sign of proportionality as

Force=K* stretch

Let’s find the value of K, using Force=132 N and stretch of 0.07 m

132 N=K*0.07 m

K=132 N/0.07 m=1885.7 N/m

Now substitute this value of K in the following equation

Force=1885.7 N/m * stretch

For a stretch of 0.1 m, the force needed is

Force=1885.7 N/m * 0.1 m=188.57 N=188.6 N

Given:
- Original price of the recliner: P
- Sale price (30% less than the original price): 0.7P
- Coupon saves an additional 25% off the sale price: 0.75 *0.7P = 0.525P
- The consumer pays $237 for the recliner.

We set up the equation:
0.525P = 237

Now, let's solve for P:

P = 237 / 0.525}
P = 451.428

Rounded to the nearest dollar, the original price of the recliner is approximately 451dollars.

To convert inches to centimeters, use the conversion factor:

1inch=2.54cm

Now, multiply:

7×2.54=17.78cm

Given the equation (x/y)-z=rw, we make x the subject of the formula as follows:

(x/y)-z=rw

Add z to both sides of the equation

(x/y)-z+z=rw+z

(x/y)=rw+z

Multiply both sides by y

(x/y)*y=y(rw+z)

X=y(rw+z)

Rearranging the equation results in:

X = y(z+rw)

In this case, we are measuring average weight of the babies with time. The weight of the babies will vary with time, meaning when we vary time, the average weight of the babies will be different. Here, time is independent while average weight is dependent variable.

Let width of the rectangle be W. We are told that length, L is 3 units greater than width. Then,

L=W+3

And perimeter of the rectangle is given by the relation, P=2(L+W]=2L+2W

In place of L substitute W+3. Thus,

P=2[W+3]+2W

Number of boxes in the room is equal to the volume of the room divided by the volume of one box

Volume of the room=9 ft*9 ft*9 ft= 729 ft3

Volume of one box = 2 ft* 2 ft * 2 ft= 8 ft3

Number of boxes= 729 ft3/ 8 ft3= 91.125 boxes

Thus, the room can store 91.125 boxes, which is about 91 boxes.

However, the room’s dimensions are 9 ft x 9 ft x 9 ft, and the boxes are 2 ft x 2 ft x 2 ft. To determine how many boxes fit along each dimension:

• In the 9 ft length, you can fit\(\frac{9}{2} = 4.5\) boxes, which means only 4 whole boxes fit along this dimension.
• In the 9 ft width, you can fit 4 whole boxes.
• In the 9 ft height, you can fit 4 whole boxes.

Therefore, the total number of boxes that fit is:

\(4×4×4=64\ boxes\)

Let the amount the friend pays be x. Then, 2 times what the friend pays is 2x. Less $2,000 what the friend pays is 2x-2000.

Now we know that

2x-2000=48000

Add 2000 to both sides of the equation

2x-2000+2000=48000+2000

2x+2000-2000=50000

2x=50000

Divide both sides by 2

X=25000

Thus, the friend pays $25,000 for their car.