The hypotenuse (side C) of a triangle is 13 inches long. Which of the following pairs of measurements could be the correct for the lengths of the other two sides of the triangle? (Note: A2 + B2= C2)

In this problem, we take the triangle as a right-angled triangle and label it as follows:

From the Pythagoras theorem A2 + B2= C2, we can look for a combination of A and B that when the squares of A and B are summed give a square of 13.  Mathematically,

But C=13 inches

If we take A=5 inches and B=12 inches, then

Next, we take A=2.5 inches, B=6 inches

Next, we take A=2.5 inches, B=4 inches

6.25+16=169

22.25≠169

Taking A=5 inches and B=8 inches

From the above computation, the combination of A=5 inches and B=12 inches give a triangle with a hypothenuse of 13 inches.

From the given scenario:

Initial charge is $40

Additional charge per circular cloth=$5c

Additional charge per rectangular cloth=$3.50r

Total cost = additional charge per circular rectangular cloths + Initial charge

Total cost, T = 5c + 3.5r + 40

Here we collect like terms together and solve for the unknown value of x.

7x-6=3x-26

Add 6 to both sides of the equation

7x-6+6=3x-26+6

7x=3x-20

Subtract 3x from both sides of the equation

7x-3x=-20

4x=-20

Divide both sides by 4

4x/-4=-20/4

x = -5

The value of x = -5

A teaspoon can approximately hold 5 mL.

Although the capacity of a teaspoon could be more or less, choice D remains the most correct answer as the other choices have amounts too much for a small teaspoon.

We are given that 1 teaspoon=4.93 mL, we can interpret it as:

Or

Since we are to find the amount in mL, we look for an option that will cancel teaspoon and remain with mL. The second option is the required conversion, and we proceed as follows:

Therefore, 2.5 teaspoons hold about 12.325 mL.

In this problem, to find one side of the square garden, we use the calculator to find the square root of 13. Thus

Thus, the approximate side of a square garden is about 3.6 ft

Here, the athlete runs 6 miles in 51 minutes, which can be expressed as:

Now, in 90 minutes, the athlete will cover about

Therefore, the athlete runs about 10.6 miles in 90 minutes.

We are given a mix of fractions and decimals and to compare the numbers, we convert the given decimals to fractions.

4.4 becomes 44/10

4.25 becomes 425/100

Now the set of fractions for comparison are: 9/2, 10/3, 44/10, and 425/100. The least common denominator for 2, 3 and 10 is 300. Then,

9/2*300=1350

10/3*300=1000

44/10*300=1320

425/10*300=1275

From the above products, 9/2 gives the greatest value when the fractions are compared with the least common denominator of the given denominators.

In the simple interest, we utilize the following formula to find the simple interest after a period of time in years.

I=P*r*t

I is the interest

P=Principal or initial deposit

r=rate

t=time in years

From the given problem, P=$600, r=6%=6/100=0.06, t=5 years. Then

I=$600*0.06*5=$180

After 5 years, Pat will earn an interest of $180.

We extrapolate the values of a line between 10 and 15 on y-axis to meet the curve and drop another line from the intersection of the curve to meet the x-axis and read off the age of the car.

Now, let’s extrapolate in the following diagram

The intersection of the line and the x-axis is between 4 and 5 years. This means that the car is about 4.5 years old. From the options given, the age of the car is more than 3 years old.