Which of the following is the correct conversion of 2 3/4 yards into inches?

Here we collect like terms together and solve for the unknown value of x.

7x-6=3x-26

Add 6 to both sides of the equation

7x-6+6=3x-26+6

7x=3x-20

Subtract 3x from both sides of the equation

7x-3x=-20

4x=-20

Divide both sides by 4

4x/-4=-20/4

x = -5

The value of x = -5

We need to perform a series of numerical dimensional analysis to find the number of bags sugar needed for 300 people.

We are told that 50 people need 4 cups of sugar. This can be interpretated as:

Or

Also, one bag of sugar contains 6 cups. This can also be presented as:

Or

We use the second option relating number of people and cups, and second option relating cups of sugar and bag of sugar to find for number of bags of sugar needed for 300 people.

Therefore, 300 people will need 4 bags of sugar.

to solve for x, we order like terms together and proceed as follows:

4x-3-5x=24

Add 3 to both sides of the equation

4x-3+3-5x=24+3

4x+3-3-5x=27

4x-5x=27

-x=27

Divide both sides by -1

-x/-1=27/-1

x= -27

Thus, the unknown value of x is -27

we are asked to change 400 mg to g. We use the conversion 1g=1000mg, which we can write as:

So, 400 mg to g becomes

We are given that 1 teaspoon=4.93 mL, we can interpret it as:

Or

Since we are to find the amount in mL, we look for an option that will cancel teaspoon and remain with mL. The second option is the required conversion, and we proceed as follows:

Therefore, 2.5 teaspoons hold about 12.325 mL.

to do a comparison of the given data set, we convert the fraction numbers into the approximate decimals.

4/3=1.333

2720=1.35

Now, we have 1.333, 1.35, 1.369, 1.357. These numbers are arranged from the smallest to the largest number, we look at the number in the second decimal place value

1.333 the number in second decimal place value is 3

1.35 the number in third decimal place value is 5

1.369 the number in third decimal place value is 6

1.357 the number in third decimal place value is 5

However, 1.35 and 1.357 have 5 in the second-place vale. We use the ird place value to compare the two number:

1.35 is same as 1.350 and the number in the third-place value is 0

1.357 the number in the third-place value is 7

Now, 0 is less than 7, and thus 1.35 is less than 1.357

Overall, 3 is less than 5, and 5 less than 6 and the provided numbers can be arranged from the smallest to the largest as:

1.333, 1.35, 1.357, 1.369

Thus, the corresponding given numbers organized from the smallest to the largest become:

4/3, 27/20, 1.357, 1.369

The greatest value is 1.369

The whole pie chart represents 100%, which we use together with the given percentages to find the respective different sports. Note that 100% is equal to 500 surveyed students. The, the number of teenagers who prefer:

Soccer

Hockey

Football

Basketball

Other

From the evaluations above, 90 teenagers love soccer, 80 love hockey, 190 teenagers love football, 120 teenagers love basketball, and 20 teenagers love others.

total muffin is equal to the sum of the different muffins sold.

Total muffins=41+27+20=88 muffins

Thus, the bakery sold about 90 muffins.

Let xxx be the amount the friend paid for their car. The problem states:

48,000=2x−2,000

Step 1: Solve for x

Add 2,000 to both sides:

48,000+2,000=2x

Divide by 2:

x=25,000

The median temperature can be found by organizing the temperature values from the smallest to the largest value as follows:

98.6, 98.7, 99.0, 99.0,99.2, 99.3, 99.7, 100.0

(for an even set of numbers, Median = frac{(frac{n}{2})th observation + (frac{n}{2} + 1) th observation}{2})

From the data set above, there are 8temperature values. The median is the temperature value in the middle position, which falls between the(frac{n}{2} th)and((frac{n}{2} + 1) th) position. Here N=8and median is found as:

(frac{(frac{n}{2})th + (frac{n}{2} + 1) th}{2} = )(frac{(frac{8}{2})th + (frac{8}{2} + 1) th }{2} = 4.5th position)

The element in the 4.5th position is the average of the 4th and 5th element.

(frac{99.0 + 99.2}{2} = 99.1)

Thus 99.1 is the median temperature.