Which of the following is the equivalence in kg for 220 lb? (2.2 lb =1 kg)

The first five months of the year are January, February, March, April, and May. We use to graph to find the amount of rainfall in each month as follows:

In the month of January, rainfall was between o and 1, which is halfway. Therefore, rainfall in January is 0.5 inches

On February, rainfall was 1 inch and on March the rainfall was 2 inches.

On April, the rainfall amount was 4 inches while on month of May, the rainfall was about 3.5 inches. Therefore, total rainfall in the first 5 months was:

Total rainfall=0.5 inches+1 inches+ 2 inches+4 inches + 3.5 inches =11 inches

We need to form a mathematical expression from the given word problem.

Let the unknown number be x.

Thrice a number is three times = 3x

Twelve less than thrice a number = 3x-12

Thus, the mathematical expression from the word problem is 3x-12

From the given data, we can draw the following triangle by letting the unknown length to be p.

We apply the Pythagoras theorem, the value of p:

The unknown length of the triangle is about 21.4 feet.

We need to find the radius of the circle from the given value of area. Then, the radius of the circle will be used to find the circumference of the circle.

The first step is to find the radius, r of the circle as

Thus, the circumference of a circle whose area is \(9\pi\ in\ ^2\)is 6 in.

Here we need to find the actual values of the additions and see the trend the student will use to estimate the given problem. The exact sum is as follows

35+192227

258+350=608

947+1032=1979

From the above calculations, it is evident that the student rounds up or down the ones place values. So, in the problem we need to approximate 694+7618.

694+7618=8312

We can approximate 8312 based on the provided choices is 8310.

In a bell-shaped curve, the data distribution is symmetric around a single peak. The centering of data around a single peak means the mean, mode and median of the test are all equal to each other.

The initial step is to convert the decimal numbers into fractions.

5.2 becomes 52/10

5.15 becomes 515/100

Next, find the least common denominator of 3, 10, and 100, which is 300. We use this value and multiply each fraction.

7/3*300=700

52/10*300=1560

13/3*300=1300

515/100*300=1545

From the above, 1560 is the greatest value which corresponds to 52/10. Thus, 5.2 is the greatest value of all the choices given.

We use 1 L =1000 mL to convert between the two units. The conversion options of interconversions are:

And

We want millimeters, use the second option to change L to mL as:

Therefore, 2.5 L is equivalent to 2500 mL.

In this scenario, we use the given scale in the charts to find the number of each coin and selected the right number of coins the student collected.

From the above evaluations, option two is the correct choice.

We are asked to find mL equivalent in 1.5 teaspoons. To carry out the operations, we utilize dimensional analysis to solve this problem as follows.

Converting between teaspoon and mL uses the following conversions:

Or

Since we want to remain with mL, use the second option and proceed as follows.

Thus, 1.5 teaspoons is equal to 7.395 mL