Which of the following is the mean of the test scores listed below?
83, 86, 76, 88, 97
97
76
86
83
Correct Answer : C
The mean of a data set is the sum of all scores divided by the number of tests.
Total test scores = 83+86+76+88+97 = 430
Number of tests = 5
Mean test score = 430/5 = 86
The mean test score is 86.
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Related Questions
Correct Answer is D
Explanation
To find the greatest number from the given options, convert the decimal numbers into fractions.
6.98 becomes 698/100
9.2 becomes 92/10
The least common denominator for the denominators of 7, 100 and 10 is 700. Now we can multiply each fraction with 700 as follows:
3/7*700=300
698/100*700=4886
10/7*700=1000
92/10*700=6440
In order from the smallest to largest, we organize the number set as follows:
3/7, 10/7, 6.98, 9.2.
Thus, 9.2 is the greatest of all.
Correct Answer is B
Explanation
We are asked to determine Japheth’s uncle’s age relating to Japheth’s age.
First, express Japheth’s uncle’s age in terms of Japheth’s age as follows
Japheth’s age=k
Japheth’s uncle’s age, u = 3k-10.
Thus, the relationship between Japheth’s uncle’s age to that of Japheth is u=3k-10.
Correct Answer is B
Explanation
Before finding the greatest number from the data set, the numbers need to be in fraction form.
-0.5=-5/10
-1.5=-15/10
The set of numbers becomes -2/3, -5/10, -15/10, -4/9
Now the least common denominator for 3, 10, and 9 is 90, which will be used to multiplied by the given fractions as follows:
-2/3*90=-60
-5/10*90=-45
-15/10*90=-135
-4/9*90=-40
From the above evaluations, the resulting numbers arranged from the smallest to the largest is -135, -60, -45, -40. Thus, the greatest number from the data set is -40, with a corresponding fraction of -4/9.
Correct Answer is D
Explanation
Percentages are fractions with denominator equal to 100. To convert a percent to decimal form, divide the value by 100.

The decimal form of 98.2% is 0.982.
Correct Answer is B
Explanation
The percentage change in weight is found in three steps below:
Absolute change in weight=final weight-initial weight
Absolute change in weight=(left|120-153 ight|=left|-33 ight|=33)
Relative change in weight=(frac{absolute change}{initial weight}=frac{33}{153}=0.216)
Percent change=relative change * 100%
Percent change=0.216*100%=21.6%
The percent change in weight lost is 21.6 %, which is about 22%.
Correct Answer is C
Explanation
Here we utilize the dimensional analysis of units of measurement of length to convert yards to cm as follows

9 yards is equal to 822.96 cm, which is about 823 cm.
Correct Answer is A
Explanation
we need to find the portion of pizza shared by other three friends.
Two friends eat half of the pizza, which is ½
And the remaining amount of pizza, 
Now, the other three friends share ½ amongst themselves equally. Then, each friend gets

The other three friends each gets 1/6 of the pizza.
Correct Answer is B
Explanation
P-At=-kr
Subtract P on both sides
P-P-At=-kr-P
-At=-kr-P
Divide both sides by -t
-At/-t=(-kr-P)/-t
A=(kr+P)/t
Correct Answer is D
Explanation
We use the given slope to find the minimum length of the ramp. In this case, slope is the ratio of height to length of the lamp. Thus,

If we let x be the minimum length of the ramp. Then,

Substituting the value of slope into the above equation results in,

Solve for value of x by cross-products

X = 18 Feet
Thus, the minimum length of the ramp needed to provide access to a door that is 1.5Â high is 18Â feet.
Correct Answer is C
Explanation
We follow the order of operations to solve the given expression. The order of operations is PEMDAS:
- Parentheses
- Exponents
- Multiplication and Division (in order from left to right)
- Addition and Subtraction (in order from left to right)
First, we start with the numerator and solve it as follows
[3(6+5*4)]
We start with multiplication in parenthesis, 5*4=20. The expression becomes
[3(6+20)]
Then, we conduct the addition in parenthesis 6+20=26. Then, the expression becomes
[3(26)]=3*26=78
Now, we solve for denominator, which is 26/2=13.
Thus, the expression is reduced into

The expression reduces into 6.
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