**Which of the following is the weight of the cargo in a truck if 1/3 of the cargo weighs 516 pounds (lb)?**

172 lb

1032 lb

1548 lb

688 lb

*Correct Answer : C*

In this problem, we assume the truck carries a whole cargo. Thus, total weight is 516 lb divided by 1/3. Thus,

We change the division sign to product and multiply 516 by reciprocal of 1/3. Then,

The weight of the cargo will be 1548 lbs.

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Related Questions

### Correct Answer is A

#### Explanation

The initial step is to convert the decimal numbers into fractions.

4.4 becomes 44/10

4.25 becomes 425/100

Thus, the set of fractions is 9/2, 44/10, 10/3, 425/100. The least common denominator for 2, 10, 3, and 100 is 300, which we use to compare each options given.

9/2*300=1350

44/10*300=1320

10/3*300=1000

425/100*300=1275

From the above, 1350 is the greatest value which corresponds to 9/2. Thus, 9/2 is the greatest value of all the choices given.

### Correct Answer is C

#### Explanation

scatter plots can of three types: positive, negative and no correlation. A positive correlation scatter plot shows that as one variable increase, the other variable increases. A positive correlation can be visually depicted below.

In a negative correlation, the change in one variable is inversely proportional to another variable. That is, as one variable increases, the other variable decreases as shown below.

The third type of scatter plot is a no-correlation scatter plot. In this type of plot, there is no defined relationship between one variable and another one as in the curve below.

If we look at the relationship between the time the student listens to music and his test score, it is evident that no relationship exists between the two variables. Thus, this is a type of **no correlation** scatter plot.

### Correct Answer is D

#### Explanation

The first three months of the year are January, February, and March. We need to find the total rainfall for these three months from the provided graph.

In the month of January, rainfall is between o and 1, which is halfway. Therefore, rainfall in January is 0.5 inches

On February, rainfall was 1 inch and on March the rainfall was 2 inches. Thus,

Total rainfall = 0.5 inches + 1 inches + 2 inches = 3.5 inches

### Correct Answer is C

#### Explanation

to convert fraction to percent, we multiply the fraction with 100. Therefore, the percent equivalent of 5/8 is

Thus, 5/8 is equal to 62.5%.

### Correct Answer is A

#### Explanation

We use 1 L =1000 mL to convert between the two units. The conversion fractions of interconverting are:

And

Since we want to end up with millimeters, the second conversion is used in converting L to mL as:

Thus, 0.5 L is equivalent to 500 mL.

### Correct Answer is C

#### Explanation

we follow the order operations to solve for the unknown value of x.

2(4x+3)=7x+5

Open the bracket on the LHS by multiplying each term by 2

(2*4x)+(2*3)=7x+5

8x+6=7x+5

Subtract 6 from both sides

8x+6-6=7x+5-6

8x=7x-1

Subtract 7x on both sides

8x-7x=7x-7x-1

X=-1

Thus, the value of unknown value of x is -1.

### Correct Answer is D

#### Explanation

: we are to find the selling price of the sweater after subtracting the mark off price.

Mark off value=mark off rate*original price

Mark of value=25%*$87

We convert 25% into a fraction, which become 25/100=0.25. Then

Mark of value=0.25*$87=$21.75

The selling price of the sweater will be the original price less the mark off value. Then,

Thus, the approximate selling price of the sweater is $65.

### Correct Answer is B

#### Explanation

We need to find how many mL are in 2.5 teaspoons. We need to use dimensional analysis to solve this problem as follows.

Converting between teaspoon and mL uses the following conversions:

Or

We want to end up with mL, we utilize the second conversion and set up the following equation.

Thus, 2.5 teaspoons can hold 12.325 mL.

### Correct Answer is A

#### Explanation

we are needed to find the amount Lana is left with after spending and investing the rest using the given information.

Amount Lana spends = 80% of $60= 80/100 *60 = $48

Amount left to invest = $(60-48) = $12

Lana is left with $12, which she invests and earns a profit of 80%.

Profit earned = 80% of $12 = 80/100 * 12= $9.20

So, Lana will have $12 + $9.20 = $21.60

### Correct Answer is B

#### Explanation

In this scenario, we use the given scale in the charts to find the number of each coin and selected the right number of coins the student collected. The second options shows that the child collected 50 pennies, 45 nickels, 25 dimes, and 5 quarters.

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