A client with impetigo receives a prescription for azithromycin (Zithromax) 500 mg PO on day 1, then 250 mg/day on days 2 through 5 for a total administration of 1.5 gram. The pharmacy has 250 mg tablets available. How many tablets total should the nurse give to the client for the duration of treatment? (Enter numeric value only.)
The Correct Answer is ["6"]
To calculate the total number of tablets needed, we'll first calculate the total amount of azithromycin required for the treatment.
Step 1: Calculate the total azithromycin required:
Total Azithromycin = Day 1 Dose + (Day 2-5 Dose x Number of Days)
Total Azithromycin = 500 mg + (250 mg x 4 days)
Total Azithromycin = 500 mg + 1000 mg
Total Azithromycin = 1500 mg
Step 2: Determine the number of tablets needed:
Number of Tablets = Total Azithromycin (mg) / Tablet Strength (mg)
Number of Tablets = 1500 mg / 250 mg/tablet
Number of Tablets = 6
Therefore, the nurse should give the client a total of 6 tablets of azithromycin for the duration of treatment.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["167"]
Explanation
To calculate the infusion rate, we'll use the following formula:
Infusion Rate (mL/hour) = Total Volume (mL) / Infusion Time (hours)
Plugging in the given values:
Infusion Rate = 1000 mL / 6 hours
Calculating the result:
Infusion Rate ≈ 166.67 mL/hour
Rounding to the nearest whole number, the nurse should program the infusion pump to deliver 167 mL/hour
Correct Answer is C
Explanation
To calculate the infusion time, we'll use the following formula:
Infusion Time (hours) = Total Volume (mL) / Infusion Rate (mL/hour)
Plugging in the given values:
Infusion Time = 1000 mL / 75 mL/hour
Calculating the result:
Infusion Time ≈ 13.33 hours
Converting hours to minutes:
0.33 hours x 60 minutes/hour ≈ 20 minutes
Therefore, the infusion will be completed approximately 13 hours and 20 minutes after it started at 0300.
Adding 13 hours and 20 minutes to 0300:
0300 + 13 hours + 20 minutes = 1620
So, the correct answer is C. 1620.
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