A client with oliguria has an order for 1000 mL of 0.9% NS over 3 hours. The tubing drop factor is 10 gtt/mL. How many gtt/min should be given? (Round to the nearest whole number. use a leading zero if it applies. Do not use a trailing zero.)
The Correct Answer is ["56"]
Flow rate (gtt/min) = Volume (mL)/Time (min) ×Drop factor (gtts/mL)
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