A nurse is preparing to administer 0.9% sodium chloride 1,000 mL IV to infuse over 4 hr. The drop factor on the manual tubing is 12 gtt/mL. The nurse should regulate the flow rate to deliver how many gtt/min? (Round the answer to the nearest whole number. Use a leading zero if it applies. Do not use a trailing zero.)
The Correct Answer is ["50"]
To calculate the flow rate in drops per minute (gtt/min), you can use the formula:
Flow rate (gtt/min) = Volume (mL) × Drop factor (gtt/mL) ÷ Time (min)
Given:
Volume = 1000 mL
Drop factor = 12 gtt/mL
Time = 4 hours
Convert 4 hours to minutes:
4 hours × 60 minutes/hour = 240 minutes
Then
Flow rate (gtt/min) = 1000 mL × 12 gtt/mL ÷ 240 min
Flow rate (gtt/min) = 12000 gtt ÷ 240 min
Flow rate (gtt/min) = 50 gtt/min
Therefore, the nurse should regulate the flow rate to deliver 50 gtt/min.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["0.3"]
Explanation
To calculate the dose of cefazolin for a neonate, first multiply the weight by the dosage per day: 5 kg x 40 mg/kg/day = 200 mg/day. Then divide by the number of doses per day: 200 mg/day / 2 doses/day = 100 mg/dose. Next, use the formula D/H x Q to find the volume to administer, where D is the dose, H is the strength of the solution, and Q is the quantity of the solution. Plug in the values: 100 mg / 330 mg/mL x 1 mL = 0.3 mL. Round to the nearest tenth: 0.3 mL. Therefore, the nurse should administer 0.3 mL of cefazolin per dose.
Correct Answer is ["1.5"]
Explanation
To calculate the amount of phenobarbital injection needed for each dose after the initial dose, we need to divide the prescribed dose (200 mg) by the concentration of the injection (130 mg/mL). This gives us:
200 mg / 130 mg/mL = 1.538 mL
To round this to the nearest tenth, we look at the hundredths place and see that it is 3, which is less than 5, so we round down and drop the rest of the digits. This gives us:
1.5 mL
Therefore, the nurse should administer 1.5 mL of phenobarbital injection per dose after the initial dose.
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