Match the growth phase with its description
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Cells die at a high rate Cells are produced at the highest rate Cells adjust to their environment New cells are produced at the same rate that old cells die |
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The Correct Answer is {"dropdown-group-1":"D","dropdown-group-2":"C","dropdown-group-3":"A","dropdown-group-4":"B"}
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Description |
Correct Growth Phase |
Rationale |
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Cells die at a high rate |
4. Death phase |
In this phase, nutrients are depleted and toxic waste accumulates, leading to a decline in viable cell numbers as death exceeds new cell formation. |
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Cells are produced at the highest rate |
3. Log phase (Exponential phase) |
Cells divide at their maximum rate, population size doubles regularly, and growth rate is logarithmic. This phase is used to test antibiotics and measure generation time. |
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Cells adjust to their environment |
1. Lag phase |
Bacteria are metabolically active but not dividing. They are synthesizing enzymes and preparing for cell division. |
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New cells are produced at the same rate that old cells die |
2. Stationary phase |
The growth curve levels off as nutrient depletion and waste buildup balance cell division and death rates. Population size remains constant. |
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is D
Explanation
A. Parasitic: A parasitic relationship benefits the microbe at the host’s expense and typically causes harm; producing vitamin K for the host does not fit the parasitic definition.
B. Saprobic: Saprobic organisms obtain nutrients from dead or decaying organic matter (decomposers); intestinal E. coli living on host-derived substrates and contributing vitamins are not acting as saprobes.
C. Antagonistic: Antagonistic interactions involve one organism inhibiting another (competition or antimicrobial production); the described vitamin-producing relationship does not reflect antagonism.
D. Mutualistic: Mutualism describes a relationship where both partners benefit — E. coli gains a habitat and nutrients while the host gains vitamin K — which fits this scenario.
Correct Answer is B
Explanation
A. Competitive: A competitive inhibitor binds at the active site, directly competing with the substrate for binding and does not change the active site shape by binding elsewhere.
B. Non-competitive: A non-competitive inhibitor binds at an allosteric (different) site, inducing a conformational change in the enzyme that alters the active site so the substrate can no longer bind effectively.
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