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Robitussin DM contains 100 mg of guaifenesin per 1 teaspoon. How many milligrams of guaifenesin are in 10 mL?

A.

200 mg

B.

100 mg

C.

75 mg

D.

50 mg

Answer and Explanation

The Correct Answer is A

Robitussin DM contains 100 mg of guaifenesin per 1 teaspoon. One teaspoon is equivalent to 5 milliliters, so 100 mg is present in 5 mL. Therefore, 10 mL of Robitussin DM contains 2 times the amount of guaifenesin in 1 teaspoon or 200 mg.


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Related Questions

Correct Answer is C

Explanation

To calculate the rate per hour, divide the amount of magnesium sulfate to be administered by the concentration of magnesium sulfate in the IV bag:

6 grams ÷ 40 grams = 0.15

Then, multiply the result by the volume of the IV bag, which is usually 1000 mL: 0.15 x 1000 mL = 150 mL

This is the amount of fluid that contains 6 grams of magnesium sulfate. To administer this amount over 30 minutes, multiply by 2 to get the rate per hour:

150 mL x 2 = 300 mL/hr.

Correct Answer is A

Explanation

First, we need to convert the weight of the child from pounds to kilograms:. 44 lb / 2.2046 = 19.958 kg (rounded to three decimal places).

Next, we can calculate the dose of glycopyrrolate:. 0.02 mg/kg x 19.958 kg = 0.39916 mg.

We should always check our calculation and verify that the dose is appropriate and safe for the child. In this case, the dose of 0.39916 mg seems reasonable for a child with chronic severe drooling..

Now, we need to determine how much medication to administer to the child. We know that 5 mL of medication contains 1 mg of drug. Therefore, to administer 0.39916 mg of glycopyrrolate, we need to administer:

(0.39916 mg / 1 mg) x 5 mL = 1.9958 mL.

We should round this dose to the nearest appropriate unit of measure. In this case, we can round to 2 mL to make it easier to measure and administer..

Therefore, the nurse should administer 2 mL of glycopyrrolate to the child three times a day (tid) to treat chronic severe drooling.

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