**3 (x-2) = 18**

**Solve the equation above for x. Which of the following is the correct answer?**

8

-5

7

4

*Correct Answer : A*

We solve for the value of x by following the order of operations

3(x-2)=15

Divide both sides of the equation by 3

Add 2 to both sides of the equation

Thus, the value of x is 8.

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Related Questions

### Correct Answer is C

#### Explanation

We use given information to find how much ammonia is need to make the specified solution.

We are told, one gallon of cleaning solution requires 10oz of ammonia. Expressing this mathematically yields two options:

\(\frac{10\ oz\ of\ ammonia}{1\ gallon\ of\ solution}\)or\(\frac{1\ gallon\ of\ solution}{10\ oz\ of\ ammonia}\)

Now we find how much ammonia is needed using option two.

\(51\ gallon\ of\ solution\ *\frac{10\ oz\ of\ ammonia}{1\ gallon\ of\ solution}\ =\ 510\ oz\ of\ ammonia\)

From the above equation, gallon of solution will cancel, and oz of ammonia is left.

Therefore, the solution will require 510 oz of ammonia.

### Correct Answer is C

#### Explanation

In this problem, we need to find the amount of gratuity the couple will leave. The gratuity is 16% of the total bill. Before solving the problem, the following are terms and their meaning in percent problems:

- Is means equals
- Of means multiply
- What means unknown (variable)

If we let x be the amount of gratuity, then translating the given problem into a mathematical equation becomes:

Now we evaluate the above equation noting that of means multiply.

So, the value of x=9.376 and to the nearest cent, x=9.38

There, a couple will leave a gratuity of $9.38.

### Correct Answer is C

#### Explanation

to find the average time the athlete runs in 1 mile; we find total distance and total time the athlete takes in running.

Total distance run by athlete=7+3=10 miles

Total time=45+15 =60 minutes

The athlete runs 10 miles in 60 minutes. For the athlete to cover 1 mile, he will run for a time less than 60 minutes. Thus, in 1 mile, the athlete takes:

So, in 6 minutes, the athlete covers 1 mile.

### Correct Answer is D

#### Explanation

Here we need to find the actual values of the additions and see the trend the student will use to estimate the given problem. The exact sum is as follows

35+192227

258+350*=*608

947+1032*=*1979

From the above calculations, it is evident that the student rounds up or down the ones place values. So, in the problem we need to approximate 694+7618.

694+7618=8312

We can approximate 8312 based on the provided choices is 8310.

### Correct Answer is C

#### Explanation

Correlation of two variables falls into:

Positive correlation: an increase in one variable causes another variable to increase

Negative correlation: an increase in one variable causes another one to decrease

No correlation: a change in one variable does not cause any response in another variable.

From the given choices

Option a is no correlation

Option b is a no correlation

Option c is a negative correlation

Option d is a positive correlation

### Correct Answer is B

#### Explanation

In this scenario, we use the given scale in the charts to find the number of each coin and selected the right number of coins the student collected.

From the above evaluations, option two is the correct choice.

### Correct Answer is A

#### Explanation

In the given problem, we use the calculator to evaluate the product 1.9 * 0.75 = 1.425

### Correct Answer is A

#### Explanation

We solve for the value of x by following the order of operations

3(x-2)=15

Divide both sides of the equation by 3

Add 2 to both sides of the equation

Thus, the value of x is 8.

### Correct Answer is C

#### Explanation

We are asked to find mL equivalent in 1.5 teaspoons. To carry out the operations, we utilize dimensional analysis to solve this problem as follows.

Converting between teaspoon and mL uses the following conversions:

Or

Since we want to remain with mL, use the second option and proceed as follows.

Thus, 1.5 teaspoons is equal to 7.395 mL

### Correct Answer is B

#### Explanation

To change between L and mL, the following two options are used.

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