A baker is using a cookie recipe that calls for 3 ¼ cups of flour to yield 64 cookies. How much flour will the baker need to make 130 cookies using the same recipe?
6 77/128 cups
5 5/128 cups
10 1/28 cups
4 81/128 cups
Correct Answer : A
we are asked to find the number of cups of flour that will be used to make 130 cookies.
First, we convert 3 ¼ into improper fraction as:
Letting x to be the number of cups of flour, we set up a proportion equation with number of cookies on numerator and number of cups of flour on the denominator becomes:
Solve the value of x by cross-products
Dividing both sides by 64, the above equation result to
Thus, the number of cups of flour needed to make 130 cookies is 845/128 cups, which is equal to 6 77/128 cups.
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Correct Answer is C
Explanation
A standard six-sided die has the numbers 1, 2, 3, 4, 5, and 6. The even numbers are 2, 4, and 6.
Step 1: Probability of rolling an even number on the first roll
There are 3 even numbers out of 6 total numbers, so:
P (evenonsecondroll) = 3/6 = ½
Step 2: Probability of rolling an even number on the second roll
Since rolling the die is an independent event, the probability remains:
P (evenonsecondroll) = 3/6 = ½
Step 3: Multiply the probabilities
P (evenonfirstANDevenonsecond) = ½ × ½ = ¼
Correct Answer is A
Explanation
To find the area of the room, we form an equation of find an equation relating the length and width of the rectangle. If we let the width of the room to be w, then
Width of the rectangle= w
Length of rectangle=(w+8)
Area of the rectangle, A= Length*width=(w+8)*w
A=w(w+8)
Thus, the area of the rectangular room is w(w+8).
Correct Answer is A
Explanation
A histogram depicts the frequency of a one variable over the other while a bar graph is used to compare two variables with vertical axis representing the heights. Therefore, a histogram will be used to represent percent of the number of students reading after 9.
Correct Answer is A
Explanation
We follow the order of operations to solve the given expression.
First, we start with the numerator and solve it as follows
[3(2+6*4)]
We start with multiplication in inner brackets, 6*4=24. The expression becomes
[3(2+24)]
Then, we conduct the addition of 2+24=26. Then, the expression becomes
[3(26)]=3*26=78
Now, we solve for denominator, which is 26/2=13.
Thus, the expression is reduced into
\(\frac{[3(2+6\ast4)]}{(26\div2)}=\frac{78}{13}=6\)
The expression reduces into 6.
Correct Answer is C
Explanation
The weight of the knife could be appropriately expressed in grams. Since a knife is a small object, we do not expect to measure its weight in kilograms. Liter and milliliter are units of measuring the volume of objects.
Correct Answer is D
Explanation
The circumference of a circle is given by the formula:
C=πd
where:
- d=16 inches
- π=3.14
Calculate the Circumference:
C=3.14×16 =50.24inches
Correct Answer is D
Explanation
we are asked to find the number of gallons a full tank can hold. A full tank is equivalent to 1.
Convert the mixed fraction into proper fraction as follows
If we let x be the number of gallons in full tank, and setting up the proportion equation with the number of gallons on the numerator and fraction of tank on denominator as follows.
Cross-multiply to find the value of x.
Converting 189/10 to a mixed fraction is 18 9/10. Thus, when the tank is full, it holds 18 9/10 gallons of water.
Correct Answer is C
Explanation
we use the relation 1 L=1000 mL to convert 3.9 L to mL as follows.
Thus, 3.9 L is 3900 mL.
Correct Answer is A
Explanation
The probability of finding the probability of a yellow ball is given by
Total number of balls in the bag=2+3+7=12 balls
The probability of drawing a yellow ball from the bag is 7/12.
Correct Answer is D
Explanation
To find the greatest number from the given options, convert the decimal numbers into fractions.
6.25 becomes 625/100
7.4 becomes 74/10
The LCM for the denominators of 8, 100, 7, and 10 is 2800. Now we can multiply each fraction with the LCM.
3/8*2800=1050
625/100*2800=17500
10/7*2800=4000
74/10*2800=20720
The fraction 7.4is the greatest of all.
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