A bucket can hold 2500 mL. How many L can the bucket hold?

To solve this problem, first find the radius of the circle.

We usea calculator to find the product of

1.6*0.93=1.488

to convert fraction to percent, multiply the fraction with 100%. Therefore, the percent equivalent of 3/4 is

3/4*100%=75%

Thus, 3/4is equal to 75%.

: In order to solve for the value of x, we use the order of operations as follows:

The first step is to divide both sides by 3

Add 2 to both sides to eliminate it from the left-hand side of the equation

x-2+2=4+2

x = 6

Thus, the value of x is 6.

We know that 1 L =1000 mL, which we use to convert between the two units. The conversion fractions of interconverting are:

And

Since we want to end up with millimeters, the second conversion is used in converting L to mL as:

Thus, 3.2 L is equivalent to 3200 mL.

The best way to visualize the student’s score for each subject is to plot them using a bar graph.

: we are needed to find the portion of burger the two other friends share between themselves. A whole burger is 1, and we know that,

One friend=1/4 of 1=1/4*1=1/4

Remaining amount=1-1/4=4/4-1/4=3/4

Thus, ¾ of burger is left for two friends to share among themselves. Then, each friend will get

So, the other two friends will each get 3/8 of the burger.

Explanation: We know that 1 L=1000 mL and to change between L and mL we use the following two options

Here we need to find the actual values of the additions and see the trend the student will use to estimate the given problem. The exact sum is as follows

35+192=227

258+350=608

947+1032=1979

From the above calculations, it is evident that the student rounds up or down the ones place values. So, in the problem we need to approximate 694+7618.

694+7618=8312

We can approximate 8312 based on the provided choices is 8310.

From the given estimations, we can find the exact sum after adding the given numbers and see the trend the student utilizes to find their estimates. The actual sum is as follows

26+180=206

115+391=506

497+2024=2521

From the above evaluation, the students round the exact sum to the nearest tens. So, in the problem we need to approximate 545+7501.

545+7501=8046

The exact sum is 8046 and the approximate value after rounding to the nearest tens is 8050.