A child has a bottle full of pennies, nickels, dimes, and quarters. There are twice as many quarters as pennies, four times as many as nickels as pennies, and five times as many dimes as nickels. How many more dimes does the child have than quarters?

We are asked to find the dependent variable from the given scenario. A dependent variable is one which varies with another variable. In this case, the cost of the pizza will change with the change in diameter of the pizza, number of toppings, and amount of cheese. In other words, the cost of the pizza depends on the three variables.

Therefore, cost is the dependent variable while the diameter of the pizza, number of toppings and amount of cheese are independent variables.

A change in number of credit hours result in a change in the amount of access fees, amount of tuition, and availability of student loans. Thus, number of credit hours is the independent variable.

We are asked to find the number of students enrolled in the respiratory care program using the percentages in the pie chart.

If we let x represent the number of students enrolled in the respiratory care program, we can set a proportion equation with number of students on the numerator and percentages on the denominator. The whole pie chart represents 100%, which is 800 students. Then, 19% will represent

We solve the value of x by cross-multiplying the equation above.

So, 152 students will enroll for a respiratory care program.

In this problem, we need to compare the number of dimes to quarters.

If we let n be number of pennies in the bottle. Then,

Number of quarters in the bottle = 2n

Number of nickels in the bottle = 4n

Number of dimes in the bottle =5(4n)=20n

Now relating dimes to quarters, we have

Thus, there are 10 times as many dimes as quarters in the box.

The slope represent the ratio between the vertical height to the horizontal length. Let x be the minimum length of the ramp, we can set a proportion with height on the numerator and length on denominator. Then,

Cross-multiply to find the value of x

Thus, the minimum length of the ramp needed is 30 feet to access to a door that is 2.5 feet above the sidewalk.

We need to find the are of the rectangle from the given case. Letting x represent the width of the rectangle. Then, we can find the area of the rectangle as follows.

Length of rectangle=(x+5)

Width of the rectangle= x

Area of the rectangle, A= Length*width=(x+5)*x

A=x(x+5)

Thus, the area of the rectangle is x(x+5).

We are being asked to find the amount of milk needed. This is a proportion problem, which compares the amount of flour to that of milk. Letting x represent the amount of milk required, we set up the proportion with flour on the numerator and amount of milk in denominator as follows:

Change the mixed fraction of 1 1/5 into improper fraction as follows

The proportion equation becomes

Cross-multiply to solve for x

As an mixed fraction, 36/5 becomes 7 1/5. Therefore, 7 1/5 cups of milk are needed to make a big batch of 2 cups.

To find the greatest number from the given options, we first convert the decimal numbers into fractions.

-0.7 becomes 7/10

-1.3 becomes 13/10

Then, we find the LCM for the denominators of the given fractions. The LCM of 3 and 10 is 30. Now we can multiply each fraction with the LCM.

-2/3*30=-20

-7/10*30=-70

-13/10*30=-39

-4/3*30=-40

Comparing the obtained values from above, -20 is the greatest followed by -39, -40, -70 in that order. The fraction -2/3 gave a value of -20, which was the greatest value. Thus, -2/3 is the greatest value from the given option.

We required to find the units of finding the weight of a spoon. The mass is measured in kilogram and grams. Kilograms are used to measure the mass of heavier objects while grams for small and lighter objects.

Thus, gram is the appropriate unit for measuring weight of a spoon.

We are asked to convert kg to pounds using the given relation. Letting x to represent the lb we are looking for.

Nest, we set the proportion with kg in the numerator and lb on the denominator as follows.

We find the value of x by cross-multiplication

The value of x is 110 lb.