A child has collected 50 pennies, 45 nickels, 25 dimes, and 5 quarters. Which of the following charts accurately organizes the number of coins?

In a bell-shaped curve, the data distribution is symmetric around a single peak. The centering of data around a single peak means the mean, mode and median of the test are all equal to each other.

To solve the equation this equation, we compute the multiplication of the two numbers using the calculator

3.60 * 0.75 = 2.7

The truck carries a whole cargo which equals 1. If we let the weight of the cargo to be p, then we set up a proportion equation with weight as numerator and fraction of cargo as denominator.

Solve for value of p by cross products

Multiply both sides by 3/2 a reciprocal of 2/3

The truck carries a cargo weighing 795 lb.

In order for the teacher to better visualize the test performance for his class, he needs to present the mark distribution in chart form. A better chart visualizer is the histogram, which will show the frequency of marks against range of test scores. A bar graph will not be used because the rectangles need to touch one another.

In a bar graph, the rectangles do not touch each other. Therefore, it will not be a good chart visualizer.

We use the order of operation to solve for the unknown value of x.

3(3x+3)=8x+5

Multiply 3 with each number in the brackets

(3*3x)+(3*3)=8x+5

9x+9=8x+5

Subtract 9 from both sides

9x+9-9=8x+5-9

9x=8x-4

Subtract 8x on both sides

9x-8x=8x-8x-4

x=-4

Thus, the unknown value of x is -4.

We use given information to find how much ammonia is need to make the specified solution.

We are told, one gallon of cleaning solution requires 10oz of ammonia. Expressing this mathematically yields two options:

\(\frac{10\ oz\ of\ ammonia}{1\ gallon\ of\ solution}\)or\(\frac{1\ gallon\ of\ solution}{10\ oz\ of\ ammonia}\)

Now we find how much ammonia is needed using option two.

\(51\ gallon\ of\ solution\ *\frac{10\ oz\ of\ ammonia}{1\ gallon\ of\ solution}\ =\ 510\ oz\ of\ ammonia\)

From the above equation, gallon of solution will cancel, and oz of ammonia is left.

Therefore, the solution will require 510 oz of ammonia.

To solve this problem, we need to have all options in fraction form.

74  95 = 

7/8 = 3/8

0.72 = 72/100

74% = 74/100

Now, find the least common denominator of 95, 8, and 100. The least common denominator is 3800, which we multiply by each fraction as follows:

74/95*3800=2960

7/8*3800=3325

72/100*3800=2736

74/100*3800=2812

We can see that the fraction 7/8 is the greatest among the given options.

A ratio is of the form a : b but can also be converted to a fraction of the form a/b, where b is not equal to zero. Besides, to in ration means per in fraction form.

In the class of 40 students, 22 are girls and 18 are boys. Thus, the ratio of girls to boys becomes:

The above fraction can be reduced further since 2 is a common factor in both 22 and 18. Thus

In ratio form, girls: boys=11:9

Thus, the ratio of girls to boys in a class of 40 students is 11 to 9.

We two conversions when asked to convert between kg and lb

And

We need kg equivalent of 220 lb, therefore we use option 1 and carry out the conversions as follows:

Thus, 100kg is equal to 220lb.

Based rainfall falling for the first 5 months, a bar graph will give a great display for the farmer to decide when start planting. The horizontal scale will represent months of the year and vertical scale will present the amount of rainfall falling.