A couple dining at a restaurant receives a bill for $38.40. They wish to leave a 15% gratuity. Which of the following is the estimated gratuity?

we are needed to find the amount Lana is left with after spending and investing the rest using the given information.

Amount Lana spends = 80% of $60= 80/100 *60 = $48

Amount left to invest = $(60-48) = $12

Lana is left with $12, which she invests and earns a profit of 80%.

Profit earned = 80% of $12 = 80/100 * 12= $9.20

So, Lana will have $12 + $9.20 = $21.60

from the given estimations, we can find the actual addition of the numbers and see a trend the student utilizes to find their estimates. The exact sum is as follows

24+190=214

151+319=470

974+1022=1996

From the above evaluation, we can clearly see the students approximates the value in the ones values. So, in the problem we need to approximate 452+5017.

452+5017=5469

We can approximate 5469 based on the provided choices to 5470.

scatter plots can of three types: positive, negative and no correlation. A positive correlation scatter plot shows that as one variable increase, the other variable increases. A positive correlation can be visually depicted below.

In a negative correlation, the change in one variable is inversely proportional to another variable. That is, as one variable increases, the other variable decreases as shown below.

The third type of scatter plot is a no-correlation scatter plot. In this type of plot, there is no defined relationship between one variable and another one as in the curve below.

If we look at the relationship between the time the student listens to music and his test score, it is evident that no relationship exists between the two variables. Thus, this is a type of no correlation scatter plot.

Correlation of two variables falls into:

Positive correlation: an increase in one variable causes another variable to increase

Negative correlation: an increase in one variable causes another one to decrease

No correlation: a change in one variable does not cause any response in another variable.

From the given choices

Option a is no correlation

Option b is a negative correlation

Option c is a negative correlation

Option d is a positive correlation

the median of a data set is the element that is found on the middle position. It is found by organizing the elements from the smallest to largest.

The data set above arranged from the smallest to largest is:

11, 12, 12, 12, 13, 14, 17, 17, 18, 22, 26

The number of elements is odd and the median is found in the (N+1)/2 th position. Here N=11, and the median falls in (11+1)/2=12/2=6 th position.

The element 14 falls in the 6th position, which is our median of the given data set.

To find the least common denominator (LCD) of the fractions 1/2, 2/3, and 4/5, follow these steps:

Step 1: Identify the denominators

The denominators are 2, 3, and 5.

Step 2: Find the least common multiple (LCM)

The LCM of 2, 3, and 5 is the smallest number that all three denominators divide into evenly.

• Prime factorization:
  • 2=2
  • 3=3
  • 5=5

Since 2, 3, and 5 are all prime numbers, their LCM is:

2×3×5=30

we are needed to find the portion of pizza shared by 3 three friends. We treat the whole pizza as 1. Now, 1 friend eats half of the whole pizza. Thus,

One friend=1/2 of 1=1/2*1=1/2

Remaining amount=1-1/2=2/2-1/2=1/2

Thus, ½ of pizza is left for three friends to share among themselves. Then, each friend will get

So, the other three friends will each get 1/6 of the pizza.

to change L to mL we use the following options of interconversions:

Or

Since we are needed to change L to mL, use the second option.

Thus, a bucket can hold 3000 mL which is equal to 3 L.

To form an equation from the word problem, first break the given statement into smaller statements.

First, we are given the width of the rectangle as x. We are told, the length is three times width. Mathematically, this means

Length=3*width=3*x=3x

Again, the length is 4 less than 3 times width of the rectangle. Thus, the length of rectangle in terms of width becomes:

Length =3x-4

This is the required equation.

The best way to display the frequency of each day of the week when students get up after 8 a.m. is by using a bar graph. Bar graphs are well-suited for representing categorical data, where each day of the week is a separate category, and the height of each bar corresponds to the count or frequency of students waking up late on that specific day.

Note: Histograms, on the other hand, are more appropriate for visualizing continuous or numerical data and are not ideal for categorical data like days of the week.Histograms are useful for understanding the distribution of data, identifying patterns, and assessing the shape of the data distribution, such as whether it's normally distributed, skewed, or has multiple modes.

As you can see below, the Histogram is used to depict a pattern/continuous/rangedata. While a bar graph does just fine even with discrete data.