A macaroni and cheese recipe calls for 1/4 cup of flour for every 1 1/6 cup of milk. To make a bigger batch, the chef uses 5 cups of flour.

Which of the following would be the amount of milk needed for the bigger batch?

We required to find the units of finding the weight of a sheet of paper. The SI unit of mass of an object is kilogram. However, kilogram is a large quantity that cannot be used to measure smaller objects.

Thus, derived units of mass are used to find the mass of other objects. In this case, the mass of a sheet paper can be recorded in grams.

By inspection, we find the corresponding values of the given denominations in the following manner.

We are asked to convert kg to pounds using the given relation. If we let x to represent the lb we are asked to find, we set the proportion equation with kg on numerator and lb on the denominator as follows.

The equivalent value of 55kg is 121 lb.

Choice A: 2 packs of Orange and 2 packs of Cream Soda

• Total drinks: 48 + 24 = 72 drinks
• Total cost: (2 * $15) + (2 * $5) = $30 + $10 = $40
• This choice not only meets the requirement of at least 60 drinks but also offers the best value in terms of cost per drink, making it the most cost-effective option.

Choice B: 3 packs of Root Beer

• Total drinks: 3 * 24 = 72 drinks
• Total cost: 3 * $14 = $42
• While this choice meets the requirement of at least 60 drinks, it's not the most cost-effective, as it costs $42for 72 drinks.

Choice C: 1 pack of Orange, 2 packs of Root Beer, and 1 pack of Cream Soda

• Total drinks: 24 + 48 + 12 = 84 drinks
• Total cost: $9 + (2 * $14) + $5 = $9 + $28 + $5 = $42
• This choice provides more than 60 drinks, but it's not the most cost-effective due to its higher cost of $42, same as choice B.

Choice D: 4 packs of Cream Soda

• Total drinks: 4 * 12 = 48 drinks
• Total cost: 4 * $5 = $20
• While this choice is the most cost effective, it falls short of providing the desired number of drinks.

we are asked to find the percent change in weight gain of a person.

First, we need to find the change in weight gained over the 4 months

Change in weight= 186-176=10 lb

The percent change is expressed as change in weight over original weight *100. Then

The percent change in weight is 6% to the nearest whole number.

To find the greatest number from the given set, we first convert the decimal numbers into fractions.

12.35 becomes 1235/100

11.46 becomes 1146/10

Then, the LCM for the denominators of the given fractions of 2, 100, 3 and 10 is 300. Now we multiply each fraction with 300, which we will use to compare the give set.

25/2*300=3750

1235/100*300=3705

40/3*300=4000

1146/10*300=3438

From the calculated values, 4000 is the greatest value. Then, 40/3is the greatest value.

We are tasked to find the unknown values of x in the given equation.

First, we add 8 to both sides of the equation.

Next, we apply the absolute rule:

If   , a>0, then u=a or u=-a

From our resulting equation, a=14, which is greater 0. Then, the first condition (u=a) becomes

Solving for x

The second condition (u= -a) becomes

Solving for x

Thus, the value of x is 4 or -3

we need to find the price of the stock on Thursday.

First, find the price changes in each day of the week as follows:

Monday’s price was $45.32

Tuesday’s price went up by $3.25 from Monday’s price. The price was $(45.32+3.25)=$48.57

Wednesday’s price decreased by $1.73 from Tuesday’s price, and so the price of the stock was $(48.57-1.73)=$46.84

Thursday’s price increased by $0.89 from Wednesday’s price, which was $(46.84+0.89)=$47.73

Therefore, the stock price on Thursday was $47.73.

The scientist found that as water temperature increases, the fish population decreases. This means that the two variables move in opposite directions—when one increases, the other decreases.

This type of relationship is called a negative correlation.

The number of boxes to fit the room is found as volume of the room divided by the volume of the box.

Number of boxes:

\(\frac{volume\ of\ the\ room}{volume\ of\ the\ box} = \frac{12ft\ *\\ 12ft\ *\ 12ft}{2.5ft\ *\ 2.5t\ *\ 2.5ft}\ =\ 110.592\)

The approximate number of boxes that can be stored in the room is approximately 111 square feet.