A math teacher obtained the following scores from a class of 45 students. Which of the following is the best way to display the frequency of each day of the week?
|
Test score |
50-59 |
60-69 |
70-79 |
80-89 |
90-99 |
|
Number of students |
10 |
4 |
9 |
20 |
2 |
Scatterplot
Pie graph
Line graph
Histogram
Correct Answer : D
In order for the teacher to better visualize the test performance for his class, he needs to present the mark distribution in chart form. A better chart visualizer is the histogram, which will show the frequency of marks against range of test scores. A bar graph will not be used because the rectangles need to touch one another.
In a bar graph, the rectangles do not touch each other. Therefore, it will not be a good chart visualizer.
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Correct Answer is D
Explanation
We use 1 L =1000 mL to convert between the two units. The conversion options of interconversions are:

And

We want millimeters, use the second option to change L to mL as:

Therefore, 2.5 L is equivalent to 2500 mL.
Correct Answer is C
Explanation
to find the average time the athlete runs in 1 mile; we find total distance and total time the athlete takes in running.
Total distance run by athlete=7+3=10 miles
Total time=45+15 =60 minutes
The athlete runs 10 miles in 60 minutes. For the athlete to cover 1 mile, he will run for a time less than 60 minutes. Thus, in 1 mile, the athlete takes:

So, in 6 minutes, the athlete covers 1 mile.
Correct Answer is A
Explanation
The truck carries a whole cargo which equals 1. If we let the weight of the cargo to be p, then we set up a proportion equation with weight as numerator and fraction of cargo as denominator.

Solve for value of p by cross products

Multiply both sides by 3/2 a reciprocal of 2/3


The truck carries a cargo weighing 795 lb.
Correct Answer is D
Explanation
Based rainfall falling for the first 5 months, a bar graph will give a great display for the farmer to decide when start planting. The horizontal scale will represent months of the year and vertical scale will present the amount of rainfall falling.
Correct Answer is A
Explanation
In the given problem, we use the calculator to evaluate the product 1.9 * 0.75 = 1.425
Correct Answer is A
Explanation
The first five months of the year are January, February, March, April, and May. We use to graph to find the amount of rainfall in each month as follows:
In the month of January, rainfall was between o and 1, which is halfway. Therefore, rainfall in January is 0.5 inches
On February, rainfall was 1 inch and on March the rainfall was 2 inches.
On April, the rainfall amount was 4 inches while on month of May, the rainfall was about 3.5 inches. Therefore, total rainfall in the first 5 months was:
Total rainfall=0.5 inches+1 inches+ 2 inches+4 inches + 3.5 inches =11 inches
Correct Answer is C
Explanation
To convert 514 to a percentage:
Step 1: Convert the mixed number to a decimal
514=5+14=5+0.25=5.255
Step 2: Convert to a percentage
Multiply by 100:
5.25×100=525%
Correct Answer is D
Explanation
To form an equation from the word problem, first break the given statement into smaller statements.
First, we are given the width of the rectangle as x. We are told, the length is three times width. Mathematically, this means
Length=3*width=3*x=3x
Again, the length is 4 less than 3 times width of the rectangle. Thus, the length of rectangle in terms of width becomes:
Length =3x-4
This is the required equation.
Correct Answer is C
Explanation
From the given data, we can draw the following triangle by letting the unknown length to be p.

We apply the Pythagoras theorem, the value of p:

The unknown length of the triangle is about 21.4 feet.
Correct Answer is C
Explanation
We use given information to find how much ammonia is need to make the specified solution.
We are told, one gallon of cleaning solution requires 10oz of ammonia. Expressing this mathematically yields two options:
\(\frac{10\ oz\ of\ ammonia}{1\ gallon\ of\ solution}\)or\(\frac{1\ gallon\ of\ solution}{10\ oz\ of\ ammonia}\)
Now we find how much ammonia is needed using option two.
\(51\ gallon\ of\ solution\ *\frac{10\ oz\ of\ ammonia}{1\ gallon\ of\ solution}\ =\ 510\ oz\ of\ ammonia\)
From the above equation, gallon of solution will cancel, and oz of ammonia is left.
Therefore, the solution will require 510 oz of ammonia.
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