A math teacher obtained the following scores from a class of 45 students. Which of the following is the best way to display the frequency of each day of the week?

Test score	50-59	60-69	70-79	80-89	90-99
Number of students	10	4	9	20	2

 

 

Here we need to find the actual values of the additions and see the trend the student will use to estimate the given problem. The exact sum is as follows

35+192227

258+350=608

947+1032=1979

From the above calculations, it is evident that the student rounds up or down the ones place values. So, in the problem we need to approximate 694+7618.

694+7618=8312

We can approximate 8312 based on the provided choices is 8310.

Scatter plots can depict three correlations: positive, negative and no correlation. A positive correlation scatter plot reveals that as one variable increases, the other variable also increases as shown below

The selling price of the sweater is marked price less the mark off value.

Mark off value=mark off rate*original price

Mark of value=30% of $95

Mark of value=0.30*$95=$28.50

Now, find the selling price of the sweater

Selling price= marked price-mark off value

Thus, the sweater will be sold for 66.50 after applying a mark off of 30%. The selling price is about $67.

We use given information to find how much ammonia is need to make the specified solution.

We are told, one gallon of cleaning solution requires 10oz of ammonia. Expressing this mathematically yields two options:

\(\frac{10\ oz\ of\ ammonia}{1\ gallon\ of\ solution}\)or\(\frac{1\ gallon\ of\ solution}{10\ oz\ of\ ammonia}\)

Now we find how much ammonia is needed using option two.

\(51\ gallon\ of\ solution\ *\frac{10\ oz\ of\ ammonia}{1\ gallon\ of\ solution}\ =\ 510\ oz\ of\ ammonia\)

From the above equation, gallon of solution will cancel, and oz of ammonia is left.

Therefore, the solution will require 510 oz of ammonia.

The median of a data set is found in two ways:

For an odd data set, the median fall in the (N+1)/2 th position.

For an even data set, the median is the average of the element in the (N/2)th and (N+1)/2 th positions.

To find the median of the given data set, we need to arrange the elements from the smallest to the largest as follows:

12, 12, 16, 18, 19, 22, 23, 24, 26, 35, 35

There are 11 elements in the data set. 11 is an odd number and the median fall in the (N+1)/2 th position.

Median =(11+1)/2=12/2=6 th position.

From the organized data, the element in the 6th position is 22, which is the required median for the data set.

To form an equation from the word problem, first break the given statement into smaller statements.

First, we are given the width of the rectangle as x. We are told, the length is three times width. Mathematically, this means

Length=3*width=3*x=3x

Again, the length is 4 less than 3 times width of the rectangle. Thus, the length of rectangle in terms of width becomes:

Length =3x-4

This is the required equation.

In the given problem, we use the calculator to evaluate the product 1.9 * 0.75 = 1.425

From the given data, we can draw the following triangle by letting the unknown length to be p.

We apply the Pythagoras theorem, the value of p:

The unknown length of the triangle is about 21.4 feet.

The truck carries a whole cargo which equals 1. If we let the weight of the cargo to be p, then we set up a proportion equation with weight as numerator and fraction of cargo as denominator.

Solve for value of p by cross products

Multiply both sides by 3/2 a reciprocal of 2/3

The truck carries a cargo weighing 795 lb.

A whole pizza represents 1, and two friends eat ¼ of the pizza. The remaining fraction of pizza is:

Remaining amount = 

Thus, 3/4 of pizza is left for three friends to share equally.

Now, the other three friends will each get

So, the other three friends will each get 1/4 of the pizza.