A patient's temperature was recorded in degrees Fahrenheit every hour for 8 hr. The temperatures in Fahrenheit were 99.0°, 99.2°, 98.7°, 99.3°, 99.7°, 98.6°, 100.0° and 99.0°. Which of the following is the median temperature?

We are given that 1 teaspoon=4.93 mL, we can interpret it as:

Or

Since we are to find the amount in mL, we look for an option that will cancel teaspoon and remain with mL. The second option is the required conversion, and we proceed as follows:

Therefore, 2.5 teaspoons hold about 12.325 mL.

In the simple interest, we utilize the following formula to find the simple interest after a period of time in years.

I=P*r*t

I is the interest

P=Principal or initial deposit

r=rate

t=time in years

From the given problem, P=$600, r=6%=6/100=0.06, t=5 years. Then

I=$600*0.06*5=$180

After 5 years, Pat will earn an interest of $180.

to do a comparison of the given data set, we convert the fraction numbers into the approximate decimals.

4/3=1.333

2720=1.35

Now, we have 1.333, 1.35, 1.369, 1.357. These numbers are arranged from the smallest to the largest number, we look at the number in the second decimal place value

1.333 the number in second decimal place value is 3

1.35 the number in third decimal place value is 5

1.369 the number in third decimal place value is 6

1.357 the number in third decimal place value is 5

However, 1.35 and 1.357 have 5 in the second-place vale. We use the ird place value to compare the two number:

1.35 is same as 1.350 and the number in the third-place value is 0

1.357 the number in the third-place value is 7

Now, 0 is less than 7, and thus 1.35 is less than 1.357

Overall, 3 is less than 5, and 5 less than 6 and the provided numbers can be arranged from the smallest to the largest as:

1.333, 1.35, 1.357, 1.369

Thus, the corresponding given numbers organized from the smallest to the largest become:

4/3, 27/20, 1.357, 1.369

The greatest value is 1.369

Here, the athlete runs 6 miles in 51 minutes, which can be expressed as:

Now, in 90 minutes, the athlete will cover about

Therefore, the athlete runs about 10.6 miles in 90 minutes.

We extrapolate the values of a line between 10 and 15 on y-axis to meet the curve and drop another line from the intersection of the curve to meet the x-axis and read off the age of the car.

Now, let’s extrapolate in the following diagram

The intersection of the line and the x-axis is between 4 and 5 years. This means that the car is about 4.5 years old. From the options given, the age of the car is more than 3 years old.

A dependent variable is one that when another variable changes, it also changes. In our case, the insurance premium changes if the age, model, mileage of car changes. Thus, insurance premium is the dependent variable while the other three are independent variable.

From the given options, we can arrange the numbers from the smallest to the largest as:

-271.906, -193.823, 145.884, 235.971

From the above, it can be noted that -271 is less than -193 while 235 is more than 145.

Round trip means to and from, which is twice the distance from home to a medical facility.

In one day, the round trip=19+19=38 miles

So, in 22 days, the round trip=38*22=836 miles.

The patient will cover 836 miles in 22 days.

Here we are required to find the area of the square of sides 3.1 m. The square is a four-sided figure with each side equal and opposite sides making 90 degrees.

Area of the square =side*side

Side=3.1 m

Area of the square =3.1 m *3.1 m=9.61 m2

Note: 3.1 + 3.1 = 6.2 which is a wrong answer.

The mean is the total divided by the number of elements in the data set. From the given data set:

Total=30+29+28+30+24+12+26+33+25+23=260

Number of items, N=10

Mean=total/N=260/10=26

The mean is 26.