A person weighed themselves at 180 lb. Three months later they weighed themselves at 160 lb. Which of the following is the percent of weight the person lost over 3 months? (Round to the nearest percent.)

We are asked to make x the subject of the formula.

First, we add z to both sides of the equation

Multiply both sides by y

The above equation can be rearranged into

Thus, the formula for finding the value of x is y(z+rw).

Centimeteris the appropriate unit to measure the length of a dollar bill.

We need to find the price changes in each day of the week in order to find the price of the stock on Thursday.

Monday’s price was $50.33

Tuesday’s price went up by $2.35 from Monday’s price. The price was $(50.33+2.35)=$52.68

Wednesday’s price decreased by $1.07 from Tuesday’s price, and so the price of the stock was $(52.68-1.07)=$51.61

Thursday’s price increased by $0.75 from Wednesday’s price, which was $(51.61+0.75)=$52.36

Therefore, the price of the stock on Thursday was $52.36.

In this problem, we need to compare the number of dimes to quarters.

If we let n be number of pennies in the bottle. Then,

Number of quarters in the bottle = 2n

Number of nickels in the bottle = 4n

Number of dimes in the bottle =5(4n)=20n

Now relating dimes to quarters, we have

Thus, there are 10 times as many dimes as quarters in the box.

7/25 is the same as 7÷25. The value becomes 0.28.

Thus, 0.28 is the decimal equivalent of 7/25.

We are asked to find the number of cups of flour that will be used to make 90 cookies.

Letting x be the number of cups of flour and setting the proportion equation with number of cookies on numerator and number of cups of flour on the denominator. We have

Solve the value of x by cross-multiplying

We convert the mixed fraction into improper fraction in order to carry out multiplication

\(x =\ \frac{9}{4}\ cups\ *\ 90\ cookies\ *\ \frac{1}{36}\ cookies\)

The number of cups of flour needed to make 90 cookies is 5.625 cups, which is equal to 5 5/8 cups(Choice B).

We are asked to find the number of gallons full tank can hold. The fraction of full tank is 1.

First, we let x be the number of gallons in full tank. Then, set the proportion equation by setting the number of gallons on the numerator and fraction of tank on denominator as follows.

Convert the mixed fraction into proper fraction and cross-multiply to find the value of x.

Converting 42/5 to a mixed fraction is 8 2/5. Thus, when the tank is full, it holds 8 2/5 gallons of water.

The best way to display the frequency of each day of the week when students get up after 8 a.m. is by using a bar graph. Bar graphs are well-suited for representing categorical data, where each day of the week is a separate category, and the height of each bar corresponds to the count or frequency of students waking up late on that specific day.

Note: Histograms, on the other hand, are more appropriate for visualizing continuous or numerical data and are not ideal for categorical data like days of the week.Histograms are useful for understanding the distribution of data, identifying patterns, and assessing the shape of the data distribution, such as whether it's normally distributed, skewed, or has multiple modes.

As you can see below, the Histogram is used to depict a pattern/continuous/rangedata. While a bar graph does just fine even with discrete data.

We need to find the value of x from the given equation. First, we move the value of 10 to the right-hand side of the equation.

Add 10 to both sides of the equation

Next, we apply the absolute rule:

,   a>0, then u=a or u=-a

In this case a=12, which is greater 0. Then, the first condition becomes

Solving for x

The second condition becomes

Solving for x

Then, the value of x is -1 or 2.

We are asked to find the Kwame’s uncle’s age in terms of Kwame’s age.

First, we need to find the age of Kwame, which is k. Then, we know that Kwame’s uncle’s age is three times that of Kwame less 17. Then,

Kwame’s uncle’s age, u = 3k-17.

Thus, the relation that relates Kwame’s uncle’s age to that of Kwame is u=3k-17.