A pharmaceutical company’s stock price was $50.33 on Monday. On Tuesday, the price went up $2.35. On Wednesday, the price decreased from Tuesday’s price by $1.07. On Thursday, the price went up $0.75 from Wednesday’s price. Which of the following was the final price on Thursday?

To find the greatest number from the given options, we first convert the decimal numbers into fractions.

4.25 becomes 425/100

4.4 becomes 44/10

Then, we find the LCM for the denominators of the given fractions. The LCM of 2, 100, 3 and 10 is 300. Now we can multiply each fraction with the LCM.

9/2*300=1350

425/100*300=1275

10/3*300=1000

44/10*300=1320

Comparing the obtained values from above, 1350 is the greatest followed by 1320, 12750, and 1000 in that order. The fraction 9/2 gave a value of 1350, which was the greatest value. Thus, 9/2 is the greatest value from the given option.

You can also convert to decimals and compare which would give you the same answer.

The mean of a data set is the total scores divided by the number of tests.

Total test scores =100+78+47+84+93+78=480

Number of tests =6

Mean test score =480/6=80

The mean test score is 80.

To find the cost-effective option, we need to find how much the consumer will spend for the given options:

2 packs of Orange and 1 pack of Cream Soda will cost $18+$5= $23

3 Packs of Orange will cost $18+$10=$28

2 packs of Root Beer and 1 pack of Cream Soda will cost 2($12)+$5=$29

5 packs of cream Soda will cost 5($5)=$25

From the above evaluation, the consumer will spend $23 for a cost effective package of soft drinks. Thus, 2 packs of Orange and 1 pack of Cream Soda will be cheaper to purchase compared to other options.

The number of boxes is determined by finding the volume of the room divided by the volume of the box.

Number of boxes

The approximate number of boxes that can be stored in the room is 92.

However, the room’s dimensions are 9 ft x 9 ft x 9 ft, and the boxes are 2 ft x 2 ft x 2 ft (unchangeable shape). To determine how many boxes fit along each dimension:

• In the 9 ft length, you can fit\(\frac{9}{2} = 4.5\ boxes\) which means only 4 whole boxes fit along this dimension.
• In the 9 ft width, you can fit 4 whole boxes.
• In the 9 ft height, you can fit 4 whole boxes.

Therefore, the total number of boxes that fit is:

\(4 \times 4 \times 4 = 64\ boxes\)

We let x represent the amount of vanilla in mL, since this is what the question is asking us to find.

Next, we will set up a proportion with number of teaspoons on the numerator and amount in mL in the denominator.

Cross-multiply to find the value of x

A recipe of 2.5 teaspoons equals 12.325 mL.

What fraction of the pizza the other three friends get is what is asked to find.

First, the pizza is whole, representing a value of 1. Then, one friend ate half of the pizza. Thun, the fraction of the pizza the friend gets is:

First friend eats =1/2 of 1=1/2

Remaining fraction of the pizza=1-1/2=1/2

Now, the three friends share ½ amongst themselves equally. Then, each friend gets

The three friends each gets 1/6 of the pizza.

To find the median, we arrange the following numbers in data set from the smallest to the largest as follows.

-3, -2, 0, 5, 10

From the above the data set, the median falls in the third position. Thus, 0 is the median for the given data set.

We need to find the value of x from the given equation. First, we move the value of 10 to the right-hand side of the equation.

Add 10 to both sides of the equation

Next, we apply the absolute rule:

,   a>0, then u=a or u=-a

In this case a=12, which is greater 0. Then, the first condition becomes

Solving for x

The second condition becomes

Solving for x

Then, the value of x is -1 or 2.

The best way to display the frequency of each day of the week when students get up after 8 a.m. is by using a bar graph. Bar graphs are well-suited for representing categorical data, where each day of the week is a separate category, and the height of each bar corresponds to the count or frequency of students waking up late on that specific day.

Note: Histograms, on the other hand, are more appropriate for visualizing continuous or numerical data and are not ideal for categorical data like days of the week.Histograms are useful for understanding the distribution of data, identifying patterns, and assessing the shape of the data distribution, such as whether it's normally distributed, skewed, or has multiple modes.

As you can see below, the Histogram is used to depict a pattern/continuous/rangedata. While a bar graph does just fine even with discrete data.

A change in number of credit hours result in a change in the amount of access fees, amount of tuition, and availability of student loans. Thus, number of credit hours is the independent variable.