An athlete can run 6 miles in 51 minutes. At this rate, how many miles could the athlete run in 90 minutes?

to solve for x, we order like terms together and proceed as follows:

4x-3-5x=24

Add 3 to both sides of the equation

4x-3+3-5x=24+3

4x+3-3-5x=27

4x-5x=27

-x=27

Divide both sides by -1

-x/-1=27/-1

x= -27

Thus, the unknown value of x is -27

Looking at the given trend, it is observed that the price increases with years. From 2008 to 2012, the price is fairly constant but we expect it to be more than $130,000 in the year 2016. The expected price in 2016 is $140,000.

Here we collect like terms together and solve for the unknown value of x.

7x-6=3x-26

Add 6 to both sides of the equation

7x-6+6=3x-26+6

7x=3x-20

Subtract 3x from both sides of the equation

7x-3x=-20

4x=-20

Divide both sides by 4

4x/-4=-20/4

x = -5

The value of x = -5

The median temperature can be found by organizing the temperature values from the smallest to the largest value as follows:

98.6, 98.7, 99.0, 99.0,99.2, 99.3, 99.7, 100.0

(for an even set of numbers, Median = frac{(frac{n}{2})th observation + (frac{n}{2} + 1) th observation}{2})

From the data set above, there are 8temperature values. The median is the temperature value in the middle position, which falls between the(frac{n}{2} th)and((frac{n}{2} + 1) th) position. Here N=8and median is found as:

(frac{(frac{n}{2})th + (frac{n}{2} + 1) th}{2} = )(frac{(frac{8}{2})th + (frac{8}{2} + 1) th }{2} = 4.5th position)

The element in the 4.5th position is the average of the 4th and 5th element.

(frac{99.0 + 99.2}{2} = 99.1)

Thus 99.1 is the median temperature.

We can interpret ‘cannot exceed” as less than ‘<’. Therefore, in our inequality, the symbol < must be included. Now let’s convert the word problem into a mathematical inequality.

Money spent on supplies=s

Money spent on textbooks=t

Total money spent=money spent on supplies + money spent on textbooks

Total money spent = s+t

But the money spent cannot exceed $12,000. Then,

s+t <$12,000.
However the money spent can still be equal to $12000, as it has not exceeded it.

Therefore, therequired inequality is s + t <= $12,000.

We convert the given weight in pounds to ounces and find total weight. 1 pound=16 ounces, which we interpret as

Or

Use the second option to convert pounds to ounces

Now, we can ounces to ounces as: 48 oz + 5 oz= 53 oz

Therefore, 3 pounds, 5 ounces is equal to 53 oz

We extrapolate the values of a line between 10 and 15 on y-axis to meet the curve and drop another line from the intersection of the curve to meet the x-axis and read off the age of the car.

Now, let’s extrapolate in the following diagram

The intersection of the line and the x-axis is between 4 and 5 years. This means that the car is about 4.5 years old. From the options given, the age of the car is more than 3 years old.

We use the properties of exponent with the same base to solve for above expression.

Multiplication of exponents with same base, we add the exponents

Division of exponents with same base, we subtract the exponents

Using these two properties, we can solve the expression:

Now we use the following properties:

y0 =1, and, thus

to do a comparison of the given data set, we convert the fraction numbers into the approximate decimals.

4/3=1.333

2720=1.35

Now, we have 1.333, 1.35, 1.369, 1.357. These numbers are arranged from the smallest to the largest number, we look at the number in the second decimal place value

1.333 the number in second decimal place value is 3

1.35 the number in third decimal place value is 5

1.369 the number in third decimal place value is 6

1.357 the number in third decimal place value is 5

However, 1.35 and 1.357 have 5 in the second-place vale. We use the ird place value to compare the two number:

1.35 is same as 1.350 and the number in the third-place value is 0

1.357 the number in the third-place value is 7

Now, 0 is less than 7, and thus 1.35 is less than 1.357

Overall, 3 is less than 5, and 5 less than 6 and the provided numbers can be arranged from the smallest to the largest as:

1.333, 1.35, 1.357, 1.369

Thus, the corresponding given numbers organized from the smallest to the largest become:

4/3, 27/20, 1.357, 1.369

The greatest value is 1.369

To answer this question, we need to observe the trend of the number of days with dollars. On day 2, the dollars were 8, after 5 days, the dollars decreased to 3, after 13 days, the dollars increased to 10. After 14 days, the dollars declined to 6 and again rose to 16 dollars after 19 days.

From this observation, we cannot be able to establishany correlation between days and dollars.