An athlete runs 7 miles in 45 minutes and then changes their pace to run the next 3 miles in 15 minutes. Overall, what is the average time in minutes it takes the athlete to run 1 mile?

to find the average time the athlete runs in 1 mile; we find total distance and total time the athlete takes in running.

Total distance run by athlete=7+3=10 miles

Total time=45+15 =60 minutes

The athlete runs 10 miles in 60 minutes. For the athlete to cover 1 mile, he will run for a time less than 60 minutes. Thus, in 1 mile, the athlete takes:

So, in 6 minutes, the athlete covers 1 mile.

Here we need to find the actual values of the additions and see the trend the student will use to estimate the given problem. The exact sum is as follows

35+192227

258+350=608

947+1032=1979

From the above calculations, it is evident that the student rounds up or down the ones place values. So, in the problem we need to approximate 694+7618.

694+7618=8312

We can approximate 8312 based on the provided choices is 8310.

Scatter plots can depict three correlations: positive, negative and no correlation. A positive correlation scatter plot reveals that as one variable increases, the other variable also increases as shown below

Based rainfall falling for the first 5 months, a bar graph will give a great display for the farmer to decide when start planting. The horizontal scale will represent months of the year and vertical scale will present the amount of rainfall falling.

We use the order of operation to solve for the unknown value of x.

3(3x+3)=8x+5

Multiply 3 with each number in the brackets

(3*3x)+(3*3)=8x+5

9x+9=8x+5

Subtract 9 from both sides

9x+9-9=8x+5-9

9x=8x-4

Subtract 8x on both sides

9x-8x=8x-8x-4

x=-4

Thus, the unknown value of x is -4.

The first five months of the year are January, February, March, April, and May. We use to graph to find the amount of rainfall in each month as follows:

In the month of January, rainfall was between o and 1, which is halfway. Therefore, rainfall in January is 0.5 inches

On February, rainfall was 1 inch and on March the rainfall was 2 inches.

On April, the rainfall amount was 4 inches while on month of May, the rainfall was about 3.5 inches. Therefore, total rainfall in the first 5 months was:

Total rainfall=0.5 inches+1 inches+ 2 inches+4 inches + 3.5 inches =11 inches

We solve for the value of x by following the order of operations

3(x-2)=15

Divide both sides of the equation by 3

Add 2 to both sides of the equation

Thus, the value of x is 8.

The median of a data set is found in two ways:

For an odd data set, the median fall in the (N+1)/2 th position.

For an even data set, the median is the average of the element in the (N/2)th and (N+1)/2 th positions.

To find the median of the given data set, we need to arrange the elements from the smallest to the largest as follows:

12, 12, 16, 18, 19, 22, 23, 24, 26, 35, 35

There are 11 elements in the data set. 11 is an odd number and the median fall in the (N+1)/2 th position.

Median =(11+1)/2=12/2=6 th position.

From the organized data, the element in the 6th position is 22, which is the required median for the data set.

To solve the equation this equation, we compute the multiplication of the two numbers using the calculator

3.60 * 0.75 = 2.7

The truck carries a whole cargo which equals 1. If we let the weight of the cargo to be p, then we set up a proportion equation with weight as numerator and fraction of cargo as denominator.

Solve for value of p by cross products

Multiply both sides by 3/2 a reciprocal of 2/3

The truck carries a cargo weighing 795 lb.