As the number of credit hours a student takes in a semester increases, the amount of tuition, the amount of access fees, and the number of student loans available also increase. Which of the following is the independent variable?

To find the cost-effective option, we need to find how much the consumer will spend for the given options:

2 packs of Orange and 1 pack of Cream Soda will cost $18+$5= $23

3 Packs of Orange will cost $18+$10=$28

2 packs of Root Beer and 1 pack of Cream Soda will cost 2($12)+$5=$29

5 packs of cream Soda will cost 5($5)=$25

From the above evaluation, the consumer will spend $23 for a cost effective package of soft drinks. Thus, 2 packs of Orange and 1 pack of Cream Soda will be cheaper to purchase compared to other options.

The mean of a data set is the total scores divided by the number of tests.

Total test scores =100+78+47+84+93+78=480

Number of tests =6

Mean test score =480/6=80

The mean test score is 80.

We convert the given value in yard to the cm using the following set up.

The value 91.44 cm is close to 90 cm. Therefore, 1 yard is approximately 90 cm.

We need to find the price changes in each day of the week in order to find the price of the stock on Thursday.

Monday’s price was $50.33

Tuesday’s price went up by $2.35 from Monday’s price. The price was $(50.33+2.35)=$52.68

Wednesday’s price decreased by $1.07 from Tuesday’s price, and so the price of the stock was $(52.68-1.07)=$51.61

Thursday’s price increased by $0.75 from Wednesday’s price, which was $(51.61+0.75)=$52.36

Therefore, the price of the stock on Thursday was $52.36.

In this problem, we need to compare the number of dimes to quarters.

If we let n be number of pennies in the bottle. Then,

Number of quarters in the bottle = 2n

Number of nickels in the bottle = 4n

Number of dimes in the bottle =5(4n)=20n

Now relating dimes to quarters, we have

Thus, there are 10 times as many dimes as quarters in the box.

The number of boxes is determined by finding the volume of the room divided by the volume of the box.

Number of boxes

The approximate number of boxes that can be stored in the room is 92.

However, the room’s dimensions are 9 ft x 9 ft x 9 ft, and the boxes are 2 ft x 2 ft x 2 ft (unchangeable shape). To determine how many boxes fit along each dimension:

• In the 9 ft length, you can fit\(\frac{9}{2} = 4.5\ boxes\) which means only 4 whole boxes fit along this dimension.
• In the 9 ft width, you can fit 4 whole boxes.
• In the 9 ft height, you can fit 4 whole boxes.

Therefore, the total number of boxes that fit is:

\(4 \times 4 \times 4 = 64\ boxes\)

We follow the order of operations to solve the given expression.

First, we start with the numerator and solve it as follows

[2(3+5*3)]

We start with multiplication in inner brackets, 5*3=15. The expression becomes

[2(3+15)]

Then, we conduct the addition of 3+15=18. Then, the expression yields

[2(18)]=2*18=36

Now, we solve for denominator, which is 12/2=6.

Thus, the expression is reduced into

The expression reduces into 6.

An independent variable is a variable that is manipulated or changed in the experiment. From the given equation, t is an independent variable, which when changed changes the values of the f(t).

We are asked to find the Kwame’s uncle’s age in terms of Kwame’s age.

First, we need to find the age of Kwame, which is k. Then, we know that Kwame’s uncle’s age is three times that of Kwame less 17. Then,

Kwame’s uncle’s age, u = 3k-17.

Thus, the relation that relates Kwame’s uncle’s age to that of Kwame is u=3k-17.

We are asked to find the number of gallons full tank can hold. The fraction of full tank is 1.

First, we let x be the number of gallons in full tank. Then, set the proportion equation by setting the number of gallons on the numerator and fraction of tank on denominator as follows.

Convert the mixed fraction into proper fraction and cross-multiply to find the value of x.

Converting 42/5 to a mixed fraction is 8 2/5. Thus, when the tank is full, it holds 8 2/5 gallons of water.