How many milliliters are there in 0.5 liters?

We follow the order of operations to solve the given expression.

First, we start with the numerator and solve it as follows

[2(3+5*3)]

We start with multiplication in inner brackets, 5*3=15. The expression becomes

[2(3+15)]

Then, we conduct the addition of 3+15=18. Then, the expression yields

[2(18)]=2*18=36

Now, we solve for denominator, which is 12/2=6.

Thus, the expression is reduced into

The expression reduces into 6.

We are asked to find the number of gallons full tank can hold. The fraction of full tank is 1.

First, we let x be the number of gallons in full tank. Then, set the proportion equation by setting the number of gallons on the numerator and fraction of tank on denominator as follows.

Convert the mixed fraction into proper fraction and cross-multiply to find the value of x.

Converting 42/5 to a mixed fraction is 8 2/5. Thus, when the tank is full, it holds 8 2/5 gallons of water.

We are asked to find the number of students enrolled in the respiratory care program using the percentages in the pie chart.

If we let x represent the number of students enrolled in the respiratory care program, we can set a proportion equation with number of students on the numerator and percentages on the denominator. The whole pie chart represents 100%, which is 800 students. Then, 19% will represent

We solve the value of x by cross-multiplying the equation above.

So, 152 students will enroll for a respiratory care program.

A change in number of credit hours result in a change in the amount of access fees, amount of tuition, and availability of student loans. Thus, number of credit hours is the independent variable.

We need to find the are of the rectangle from the given case. Letting x represent the width of the rectangle. Then, we can find the area of the rectangle as follows.

Length of rectangle=(x+5)

Width of the rectangle= x

Area of the rectangle, A= Length*width=(x+5)*x

A=x(x+5)

Thus, the area of the rectangle is x(x+5).

To find the greatest number from the given options, we first convert the decimal numbers into fractions.

-0.7 becomes 7/10

-1.3 becomes 13/10

Then, we find the LCM for the denominators of the given fractions. The LCM of 3 and 10 is 30. Now we can multiply each fraction with the LCM.

-2/3*30=-20

-7/10*30=-70

-13/10*30=-39

-4/3*30=-40

Comparing the obtained values from above, -20 is the greatest followed by -39, -40, -70 in that order. The fraction -2/3 gave a value of -20, which was the greatest value. Thus, -2/3 is the greatest value from the given option.

The best way to display the frequency of each day of the week when students get up after 8 a.m. is by using a bar graph. Bar graphs are well-suited for representing categorical data, where each day of the week is a separate category, and the height of each bar corresponds to the count or frequency of students waking up late on that specific day.

Note: Histograms, on the other hand, are more appropriate for visualizing continuous or numerical data and are not ideal for categorical data like days of the week.Histograms are useful for understanding the distribution of data, identifying patterns, and assessing the shape of the data distribution, such as whether it's normally distributed, skewed, or has multiple modes.

As you can see below, the Histogram is used to depict a pattern/continuous/rangedata. While a bar graph does just fine even with discrete data.

We let x represent the amount of vanilla in mL, since this is what the question is asking us to find.

Next, we will set up a proportion with number of teaspoons on the numerator and amount in mL in the denominator.

Cross-multiply to find the value of x

A recipe of 2.5 teaspoons equals 12.325 mL.

To find the median, we arrange the following numbers in data set from the smallest to the largest as follows.

-3, -2, 0, 5, 10

From the above the data set, the median falls in the third position. Thus, 0 is the median for the given data set.

We need to find the value of x from the given equation. First, we move the value of 10 to the right-hand side of the equation.

Add 10 to both sides of the equation

Next, we apply the absolute rule:

,   a>0, then u=a or u=-a

In this case a=12, which is greater 0. Then, the first condition becomes

Solving for x

The second condition becomes

Solving for x

Then, the value of x is -1 or 2.