Which of the following is the length of the unknown leg of a right triangle that has one leg length of 10 feet and a hypotenuse of 14 feet? (Round to the nearest tenth.)

We required to find the units of finding the weight of a sheet of paper. The SI unit of mass of an object is kilogram. However, kilogram is a large quantity that cannot be used to measure smaller objects.

Thus, derived units of mass are used to find the mass of other objects. In this case, the mass of a sheet paper can be recorded in grams.

To find the probability of an event, we use the following the formula

To find the probability of drawing the red ball, we need to find the total number of balls in the bag.

Total number of balls in the bag=6+3+5=14 balls

The probability of drawing a red ball from the bag is 3/14.

we are asked to find the percent change in weight gain of a person.

First, we need to find the change in weight gained over the 4 months

Change in weight= 186-176=10 lb

The percent change is expressed as change in weight over original weight *100. Then

The percent change in weight is 6% to the nearest whole number.

We are tasked to find the unknown values of x in the given equation.

First, we add 8 to both sides of the equation.

Next, we apply the absolute rule:

If   , a>0, then u=a or u=-a

From our resulting equation, a=14, which is greater 0. Then, the first condition (u=a) becomes

Solving for x

The second condition (u= -a) becomes

Solving for x

Thus, the value of x is 4 or -3

we are asked to find the number of gallons a full tank holds. A full tank is treated as 1 whole.

Letting x be the number of gallons in full tank and setting the proportion equation with the number of gallons on the numerator and fraction of tank on denominator as follows.

Convert the mixed fraction into proper fraction and cross-multiply to find the value of x.

x 1 full tank=185 gallons23full tank

A full tank holds 27/5 gallons, which when converted to a mixed fraction is 5 2/5.

we set the conversion equation to find the unknown unit. Arrange the equation such that the unwanted units cancel out and the wanted unit remains.

The value 365.76 cm is close to 365 cm. Therefore, 4 yards is approximately 365 cm.

Choice A: 2 packs of Orange and 2 packs of Cream Soda

• Total drinks: 48 + 24 = 72 drinks
• Total cost: (2 * $15) + (2 * $5) = $30 + $10 = $40
• This choice not only meets the requirement of at least 60 drinks but also offers the best value in terms of cost per drink, making it the most cost-effective option.

Choice B: 3 packs of Root Beer

• Total drinks: 3 * 24 = 72 drinks
• Total cost: 3 * $14 = $42
• While this choice meets the requirement of at least 60 drinks, it's not the most cost-effective, as it costs $42for 72 drinks.

Choice C: 1 pack of Orange, 2 packs of Root Beer, and 1 pack of Cream Soda

• Total drinks: 24 + 48 + 12 = 84 drinks
• Total cost: $9 + (2 * $14) + $5 = $9 + $28 + $5 = $42
• This choice provides more than 60 drinks, but it's not the most cost-effective due to its higher cost of $42, same as choice B.

Choice D: 4 packs of Cream Soda

• Total drinks: 4 * 12 = 48 drinks
• Total cost: 4 * $5 = $20
• While this choice is the most cost effective, it falls short of providing the desired number of drinks.

To find the greatest number from the given set, we first convert the decimal numbers into fractions.

12.35 becomes 1235/100

11.46 becomes 1146/10

Then, the LCM for the denominators of the given fractions of 2, 100, 3 and 10 is 300. Now we multiply each fraction with 300, which we will use to compare the give set.

25/2*300=3750

1235/100*300=3705

40/3*300=4000

1146/10*300=3438

From the calculated values, 4000 is the greatest value. Then, 40/3is the greatest value.

the mean of a data set is the sum of the scores divided by the number of tests.

Total test scores =99+93+67+ 48+ 92+ 87=486

Number of tests =6

Mean test score =486/6=81

The mean test score is 81.

The number of boxes to fit the room is found as volume of the room divided by the volume of the box.

Number of boxes:

\(\frac{volume\ of\ the\ room}{volume\ of\ the\ box} = \frac{12ft\ *\\ 12ft\ *\ 12ft}{2.5ft\ *\ 2.5t\ *\ 2.5ft}\ =\ 110.592\)

The approximate number of boxes that can be stored in the room is approximately 111 square feet.