Japheth’s uncle is 10 less than three times Japheth’s age. Which of the equations represents Japheth’s uncle’s age (u) as it relates to Japheth’s age (k)?

The number of cups of milk to make a bigger batch, we proceed as follows:

First convert the mixed number 1 2/5 as

Then, we let the unknown number of cups of milk to be x and we set a proportion equation with number cups of floor as numerator and cups of milk as denominator

Find the value of x by cross-products

2 as a fraction is 2/1 which is then used to find the product of the numerator as follows.

Per means division. The above equation becomes

When dividing fractions, we multiply the first fraction with the reciprocal of the second. The reciprocal of 2/9 is 9/2. Thus

The numbers of cups of milk required is 63/5, which when converted to mixed fraction becomes 12 3/5.

We need to find the radius of the circle in order to find circumference of the circle. If we let r to be radius of the circle, then

Substituting 169π in place of area

Dividing both sides by pi and taking square root on both sides yields

The radius of the circle from the given area is 13 in. and the circumference of the circle is given by the relation:

We are asked to determine Japheth’s uncle’s age relating to Japheth’s age.

First, express Japheth’s uncle’s age in terms of Japheth’s age as follows

Japheth’s age=k

Japheth’s uncle’s age, u = 3k-10.

Thus, the relationship between Japheth’s uncle’s age to that of Japheth is u=3k-10.

The volume V of a rectangular box can be calculated using the formula:

V=length×width×height

Given:

• Length = 8 metres
• Width = 5 metres
• Height = 3 metres

Now, calculate the volume:

V=8 m×5 m×3 m=120 m3

Thus, the volume of the box is 120 cubic metres.

The correct answer is B. 120 m³.

Here we utilize the dimensional analysis of units of measurement of length to convert yards to cm as follows

9 yards is equal to 822.96 cm, which is about 823 cm.

P-At=-kr

Subtract P on both sides

P-P-At=-kr-P

-At=-kr-P

Divide both sides by -t

-At/-t=(-kr-P)/-t

A=(kr+P)/t

we find the value of x by applying the absolute conditions to the given equation.

First, add 2 to both sides of equation

The absolute conditions are:

If   , a>0, then u=a or u=-a

In this case a=10, which is greater 0.

The first condition becomes

Add 2 to both sides of the equation

Divide both sides by 4

The second condition becomes

Add 2 to both sides of the equation

Divide both sides by 4

Then, the value of x is 3 or -2.

Given:

• 2 teaspoons of baking powder for every ½ cup of flour.
• We are using 5 cups of flour.

Step 1: Determine how many teaspoons are needed per cup of flour.

Since the recipe calls for 2 teaspoons for every ½ cup of flour, the number of teaspoons required for 1 full cup of flour would be:

2 teaspoons×2=4 teaspoonspercup.

Step 2: Calculate how many teaspoons are needed for 5 cups of flour.

Now, multiply the number of teaspoons needed for 1 cup of flour by 5:

4 teaspoonspercup×5 cups=20 teaspoons.

Thus, the number of teaspoons of baking powder needed for 5 cups of flour is 20 teaspoons.

Therefore, the correct answer is D. 20 tsp.

We follow the order of operations to solve the given expression. The order of operations is PEMDAS:

• Parentheses
• Exponents
• Multiplication and Division (in order from left to right)
• Addition and Subtraction (in order from left to right)

First, we start with the numerator and solve it as follows

[3(6+5*4)]

We start with multiplication in parenthesis, 5*4=20. The expression becomes

[3(6+20)]

Then, we conduct the addition in parenthesis 6+20=26. Then, the expression becomes

[3(26)]=3*26=78

Now, we solve for denominator, which is 26/2=13.

Thus, the expression is reduced into

The expression reduces into 6.

Here, we are required to find the unit of measuring mass. The SI unit of mass is kilogram but other derived units are grams, milligrams, microgram and more.

A kilogram is a large quantity for measuring heavier objects but grams can used to measure small and light objects such as the mass of the mobile phone. Therefore, gram is the appropriate unit for measuring weight of a mobile phone.