John’s uncle is twelve less than five times John’s age. Which of the equations represents John’s uncle’s age (u) as it relates to John’s age (k)?

 we use the relation 1 L=1000 mL to convert 3.9 L to mL as follows.

Thus, 3.9 L is 3900 mL.

To find the area of the room, we form an equation of find an equation relating the length and width of the rectangle. If we let the width of the room to be w, then

Width of the rectangle= w

Length of rectangle=(w+8)

Area of the rectangle, A= Length*width=(w+8)*w

A=w(w+8)

Thus, the area of the rectangular room is w(w+8).

we are asked to find the number of gallons a full tank can hold. A full tank is equivalent to 1.

Convert the mixed fraction into proper fraction as follows

If we let x be the number of gallons in full tank, and setting up the proportion equation with the number of gallons on the numerator and fraction of tank on denominator as follows.

Cross-multiply to find the value of x.

Converting 189/10 to a mixed fraction is 18 9/10. Thus, when the tank is full, it holds 18 9/10 gallons of water.

 To find the minimum length requires, we need to understand what slope in the question represents. The slope represents the ratio between the height to the length. Let x be the minimum length of the ramp. Then,

Now, we find the value of x by cross-products as follows

Thus, the minimum length required to provide access is 60 feet.

To determine the number of sophomore students, follow these steps:

1. Identify the total number of students:

1,276

1. Identify the percentage of sophomores:

29%

1. Calculate the number of sophomores:

(29%×1,276) = (29/100× 1,276) = 370.04

1. Round to the nearest whole number:

370

We are asked to determine John’s uncle’s age relating to John’s age.

First, express John’s uncle’s age in terms of John’s age as follows

John’s age=k

John’s uncle’s age, u = 5k-12.

Thus, the relationship between Japheth’s uncle’s age to that of Japheth is u=5k-12.

Based on the given case, the outcome of measuring the duration of opening the bank is the amount of transaction, the number of deposits, and the number of loans available. The three outcomes are dependent variables while the number of opening hours is the independent variable.

 the percentage change in weight is found by calculating change in weight over original multiplied by 100%.

First, find the change in weight over the 3 months

Change in weight lost= 1860-130=30 lb

Thus

The percent change in weight is 19% to the nearest whole number.

We follow the order of operations to solve the given expression.

First, we start with the numerator and solve it as follows

[3(2+6*4)]

We start with multiplication in inner brackets, 6*4=24. The expression becomes

[3(2+24)]

Then, we conduct the addition of 2+24=26. Then, the expression becomes

[3(26)]=3*26=78

Now, we solve for denominator, which is 26/2=13.

Thus, the expression is reduced into

\(\frac{[3(2+6\ast4)]}{(26\div2)}=\frac{78}{13}=6\)

The expression reduces into 6.

 We are asked to convert kg to pounds using the given relation. Letting x to represent the lb we are looking for.

Nest, we set the proportion with kg in the numerator and lb on the denominator as follows.

We find the value of x by cross-multiplication

The value of x is 110 lb.