Kwame’s uncle is seventeen less than three times Kwame’s age. Which of the equations represents Kwame’s uncle’s age (u) as it relates to Kwame’s age (k)?

To find the median, we arrange the following numbers in data set from the smallest to the largest as follows.

-3, -2, 0, 5, 10

From the above the data set, the median falls in the third position. Thus, 0 is the median for the given data set.

We are asked to find the Kwame’s uncle’s age in terms of Kwame’s age.

First, we need to find the age of Kwame, which is k. Then, we know that Kwame’s uncle’s age is three times that of Kwame less 17. Then,

Kwame’s uncle’s age, u = 3k-17.

Thus, the relation that relates Kwame’s uncle’s age to that of Kwame is u=3k-17.

An independent variable is a variable that is manipulated or changed in the experiment. From the given equation, t is an independent variable, which when changed changes the values of the f(t).

We are asked to make x the subject of the formula.

First, we add z to both sides of the equation

Multiply both sides by y

The above equation can be rearranged into

Thus, the formula for finding the value of x is y(z+rw).

7/25 is the same as 7÷25. The value becomes 0.28.

Thus, 0.28 is the decimal equivalent of 7/25.

We let x represent the amount of vanilla in mL, since this is what the question is asking us to find.

Next, we will set up a proportion with number of teaspoons on the numerator and amount in mL in the denominator.

Cross-multiply to find the value of x

A recipe of 2.5 teaspoons equals 12.325 mL.

The mean of a data set is the total scores divided by the number of tests.

Total test scores =100+78+47+84+93+78=480

Number of tests =6

Mean test score =480/6=80

The mean test score is 80.

We are asked to convert kg to pounds using the given relation. Letting x to represent the lb we are looking for.

Nest, we set the proportion with kg in the numerator and lb on the denominator as follows.

We find the value of x by cross-multiplication

The value of x is 110 lb.

The number of boxes is determined by finding the volume of the room divided by the volume of the box.

Number of boxes

The approximate number of boxes that can be stored in the room is 92.

However, the room’s dimensions are 9 ft x 9 ft x 9 ft, and the boxes are 2 ft x 2 ft x 2 ft (unchangeable shape). To determine how many boxes fit along each dimension:

• In the 9 ft length, you can fit\(\frac{9}{2} = 4.5\ boxes\) which means only 4 whole boxes fit along this dimension.
• In the 9 ft width, you can fit 4 whole boxes.
• In the 9 ft height, you can fit 4 whole boxes.

Therefore, the total number of boxes that fit is:

\(4 \times 4 \times 4 = 64\ boxes\)

We need to find the price changes in each day of the week in order to find the price of the stock on Thursday.

Monday’s price was $50.33

Tuesday’s price went up by $2.35 from Monday’s price. The price was $(50.33+2.35)=$52.68

Wednesday’s price decreased by $1.07 from Tuesday’s price, and so the price of the stock was $(52.68-1.07)=$51.61

Thursday’s price increased by $0.75 from Wednesday’s price, which was $(51.61+0.75)=$52.36

Therefore, the price of the stock on Thursday was $52.36.